如果您的唯一目标是检查php中是否存在行(true或false),那么最好的方法是什么?
选项1?
$result = mysql_query("SELECT * FROM users WHERE id = '1'");
$num_rows = mysql_num_rows($result);
if ($num_rows == 1)
// one user, like it should be.
else
// do something else
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选项2?
$query = mysql_query("select count(1) from users where id = 1")
if (mysql_result($query, 0) == 1)
// one user, like it should be.
else
// do something else
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选项3?
$query = mysql_query("something like SELECT EXISTS( SELECT */1/COUNT(*)/etc. ...)")
if (mysql_result($query, 0) == 1)
// one user, like it should be.
else
// do something else
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Beter选项4?
你说出来的.
子问题
COUNT(*), COUNT(1) or COUNT(id)?如果您使用MySQL,选项3是检查行是否存在的最快方法:
$query = mysql_query("SELECT EXISTS(SELECT 1 FROM users WHERE id = 1)")
if (mysql_result($query, 0) == 1)
// one user, like it should be.
else
// do something else
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