Python raw_input忽略换行符

Question

有没有办法忽略通过raw_input输入的数据中的换行符？我正在尝试使用raw_input输入从电子表格中复制和粘贴的字符串列表.问题是看起来新行字符会导致数据过早输入.无论如何,所有空白空间都将被剥离,因此在输入数据时删除换行符将是一个额外的好处.此数据需要通过终端提示直接输入,而不是从文件中读取.

这是我到目前为止所做的:

names = raw_input('Shoot me some names partner: ')

print 'What do you want to do?'
print '1 - format names for program 1'
print '2 - format names for program 2'

first_act = raw_input('Enter choice: ')

print names
print first_act

现在,当我运行这个并输入虚拟名称时,我将其放入google doc电子表格进行测试,一旦我按下shift + ctl + v,没有按Enter键,我得到这个:

seth@linux-1337:~> python pythonproj/names.py
Shoot me some names partner: abcd,efg,hijkl,mnop
abcd,efg,hijkl,mnop
abcd,efg,hijkl,mnop
abcd,efg,hijkl,mnop
abcd,efg,hijkl,mnop
abcd,efg,hijkl,mnop
abcd,efg,hijkl,mnop
abcd,efg,hijkl,mnopWhat do you want to do?
1 - format names for program 1
2 - format names for program 2
Enter choice: abcd,efg,hijkl,mnop
abcd,efg,hijkl,mnop
seth@linux-1337:~> abcd,efg,hijkl,mnop
If 'abcd,efg,hijkl,mnop' is not a typo you can use command-not-found to lookup the package that contains it, like this:
cnf abcd,efg,hijkl,mnop
seth@linux-1337:~> abcd,efg,hijkl,mnop
If 'abcd,efg,hijkl,mnop' is not a typo you can use command-not-found to lookup the package that contains it, like this:
cnf abcd,efg,hijkl,mnop
seth@linux-1337:~> abcd,efg,hijkl,mnop
If 'abcd,efg,hijkl,mnop' is not a typo you can use command-not-found to lookup the package that contains it, like this:
cnf abcd,efg,hijkl,mnop
seth@linux-1337:~> abcd,efg,hijkl,mnop
If 'abcd,efg,hijkl,mnop' is not a typo you can use command-not-found to lookup the package that contains it, like this:
cnf abcd,efg,hijkl,mnop
seth@linux-1337:~> abcd,efg,hijkl,mnop
If 'abcd,efg,hijkl,mnop' is not a typo you can use command-not-found to lookup the package that contains it, like this:
cnf abcd,efg,hijkl,mnop
seth@linux-1337:~> abcd,efg,hijkl,mnop

我是python的新手,到目前为止我不是最有经验的程序员.这是python 2.7.

Answer 1

因为raw_input只需要输入一行,您需要创建一个循环:

names = []
print('Shoot me some names partner: ')
while True:
    try:
        name = raw_input()
    except KeyboardInterrupt:
        break
    names.append(name)

print('What do you want to do?')
print('1 - format names for program 1')
print('2 - format names for program 2')

first_act = raw_input('Enter choice: ')

print(names)
print(first_act)

测试运行:

Shoot me some names partner: 
name1
name2
^CWhat do you want to do?
1 - format names for program 1
2 - format names for program 2
Enter choice: 1
['name1', 'name2']
1

注意我在这里使用^C(Ctrl-C)来表示输入的结束.

Answer 2

我不确定你想问什么，但是当你使用 raw_input() 时，它会删除尾随换行符。

医生也这么说。

如果存在提示参数，则会将其写入标准输出，且不带尾随换行符。然后该函数从输入中读取一行，将其转换为字符串（去除尾随换行符），然后返回该字符串。当读取 EOF 时，会引发 EOFError。