Kev*_*inM 9 database sqlite prepared-statement nslog ios
我正在插入或替换到我的sqlite数据库中的数据有一些意想不到的结果.为了解决这个问题,我试图在下面的代码中从准备好的sqlite3_stmt(语句)中获得完整的打印.
我想做的是这样的事情,但我知道它不起作用:
if (sqlite3_step(statement) == SQLITE_DONE) {
NSLog(@"%@", statement);
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反正有没有完成这个?
谢谢!!
sqlite3_stmt *statement;
const char *dbPath = [databasePath UTF8String];
if (true) {
ListingsObject *temp = (ListingsObject *) DatabaseObject;
if (sqlite3_open(dbPath, &conyDB) == SQLITE_OK) {
const char *insertReplaceStmt = "INSERT OR REPLACE INTO listings (id, association_id, name, email, phone, toll_free_phone, fax, website, street, city, state, zipcode, county, bio, featured, hours, lat, lng, updated, status) VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)";
if (sqlite3_prepare_v2(conyDB, insertReplaceStmt, -1, &statement, NULL) == SQLITE_OK) {
sqlite3_bind_text(statement, 1, [temp._id UTF8String], -1, SQLITE_TRANSIENT);
sqlite3_bind_text(statement, 2, [temp.associationId UTF8String], -1, SQLITE_TRANSIENT);
sqlite3_bind_text(statement, 3, [temp.name UTF8String], -1, SQLITE_TRANSIENT);
sqlite3_bind_text(statement, 4, [temp.email UTF8String], -1, SQLITE_TRANSIENT);
sqlite3_bind_text(statement, 5, [temp.phone UTF8String], -1, SQLITE_TRANSIENT);
sqlite3_bind_text(statement, 6, [temp.tollFreePhone UTF8String], -1, SQLITE_TRANSIENT);
sqlite3_bind_text(statement, 7, [temp.fax UTF8String], -1, SQLITE_TRANSIENT);
sqlite3_bind_text(statement, 8, [temp.website UTF8String], -1, SQLITE_TRANSIENT);
sqlite3_bind_text(statement, 9, [temp.street UTF8String], -1, SQLITE_TRANSIENT);
sqlite3_bind_text(statement, 10, [temp.city UTF8String], -1, SQLITE_TRANSIENT);
sqlite3_bind_text(statement, 11, [temp.state UTF8String], -1, SQLITE_TRANSIENT);
sqlite3_bind_text(statement, 12, [temp.zipcode UTF8String], -1, SQLITE_TRANSIENT);
sqlite3_bind_text(statement, 13, [temp.county UTF8String], -1, SQLITE_TRANSIENT);
sqlite3_bind_text(statement, 14, [temp.bio UTF8String], -1, SQLITE_TRANSIENT);
sqlite3_bind_text(statement, 15, [temp.featured UTF8String], -1, SQLITE_TRANSIENT);
sqlite3_bind_text(statement, 16, [temp.hours UTF8String], -1, SQLITE_TRANSIENT);
sqlite3_bind_text(statement, 17, [temp.lat UTF8String], -1, SQLITE_TRANSIENT);
sqlite3_bind_text(statement, 18, [temp.lng UTF8String], -1, SQLITE_TRANSIENT);
sqlite3_bind_text(statement, 19, [temp.updated UTF8String], -1, SQLITE_TRANSIENT);
sqlite3_bind_text(statement, 20, [temp.status UTF8String], -1, SQLITE_TRANSIENT);
}
if (sqlite3_step(statement) == SQLITE_DONE) {
NSLog(@"Insert or Replace to Listing Table successful Listing = %@", temp.name);
}else {
NSLog(@"Failed to add to Listing table Listing = %@", temp.name);
}
sqlite3_finalize(statement);
}
sqlite3_close(conyDB);
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更新:我还没有找到这个问题的答案.但我需要继续前进,所以我最终只是用NSLog()构建一个字符串; 如下所示,我必须检查每一张桌子:
NSLog(@" INSERT OR REPLACE INTO listings (id, association_id, name, email, phone, toll_free_phone, fax, website, street, city, state, zipcode, county, bio, featured, hours, lat, lng, updated, status) VALUES (\"%@\", \"%@\", \"%@\", \"%@\", \"%@\", \"%@\", \"%@\", \"%@\", \"%@\", \"%@\", \"%@\", \"%@\", \"%@\", \"%@\", \"%@\", \"%@\", \"%@\", \"%@\", \"%@\", \"%@\")", temp._id, temp.associationId, temp.name, temp.email, temp.phone, temp.tollFreePhone, temp.fax
, temp.website, temp.street, temp.city, temp.state, temp.zipcode, temp.county, temp.bio, temp.featured, temp.hours, temp.lat, temp.lng, temp.updated, temp.status);
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我没有找到任何标准方法,所以我自己做了:
-(NSMutableString*) sqlite3StmtToString:(sqlite3_stmt*) statement
{
NSMutableString *s = [NSMutableString new];
[s appendString:@"{\"statement\":["];
for (int c = 0; c < sqlite3_column_count(statement); c++){
[s appendFormat:@"{\"column\":\"%@\",\"value\":\"%@\"}",[NSString stringWithUTF8String:(char*)sqlite3_column_name(statement, c)],[NSString stringWithUTF8String:(char*)sqlite3_column_text(statement, c)]];
if (c < sqlite3_column_count(statement) - 1)
[s appendString:@","];
}
[s appendString:@"]}"];
return s;
}
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你这样称呼它:
NSLog(@"%@",[self sqlite3StmtToString:statement]);
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观察:我在同一个班级做过,因为我打电话给self你,但你可以在任何一个班级做
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