Python:将多个列表连接到一个句子

Question

你好,我有多个清单.例如:

[u'This/ABC']
[u'is/ABC']
[u'not/ABC']
[u'even/ABC']
[u'close/ABC']
[u'to/ABC']
[u'funny/ABC']
[u'./ABC']

[u'O/ABC']
[u'noez/ABC']
[u'!/ABC']

我需要加入此列表

This/ABC is/ABC not/ABC even/ABC close/ABC to/ABC funny/ABC ./ABC

O/ABC noez/ABC !/ABC

我该怎么办？是的,中间有空的空间!

Answer 1

如果将它们全部放在列表中,例如:

a = [
    [u'This/ABC'],
    [u'is/ABC'],
    ...
]

您可以通过添加所有列表并在结果上使用常规联接来获得结果:

result = ' '.join(sum(a, []))

在重新阅读这个问题几次之后,我想你也想要那个空行.这更像是一样的.加:

b = [
    [u'O/ABC'],
    [u'HAI/ABC'],
    ...
]

lines = [a, b]

result = '\n\n'.join([' '.join(sum(line, [])) for line in lines])