Mik*_*ike 9 php arrays ajax json
我正试图通过ajax发布数据,这是我的信息:
var jsondata =
{"address" : [
{ "id": addid, "streetaddress": streetaddress, "city": city, "state": state, "zipcode": zipcode, "latitude": latitude},
]
};
var jsontosend = JSON.stringify(jsondata, null, 2);
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ajax功能:
$.ajax({
type: "POST",
url: "process.php",
contentType: "application/json; charset=utf-8",
dataType: "JSON",
data: jsontosend,
success: function(msg){
alert(msg);
}
});
return false;
alert('Data sent');
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}
在php结束时,当我print_r($ _ POST)它只是说
array(0) {
}
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我正在警告(jsontosend)并且它完美地展示了我的一切,以及使用post mothod的firebug,它以完美的清洁方式显示所有的参数.
它传递任何数据的唯一方法是使用GET方法.
任何意见是极大的赞赏!
编辑:从firebug添加POST数据.这是警报功能提醒的:
{"address":[{"id":1473294,"streetaddress":"3784 Howard Ave","city":"Washington DC","state":"DC","zipcode":20895,"latitude":39.027820587}]}
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这是firebug在使用POST方法时传递的内容:
myData=%7B%0A++++%22address%22%3A+%5B%0A++++++++%7B%0A++++++++++++%22id%22%3A+76076%2C%0A++++++++++++%22streetaddress%22%3A+%223784+Howard+Ave%22%2C%0A++++++++++++%22city%22%3A+%22Washington+DC%22%2C%0A++++++++++++%22state%22%3A+%22DC%22%2C%0A++++++++++++%22zipcode%22%3A+20895%2C%0A++++++++++++%22latitude%22%3A+39.027820587%0A++++++++%7D%0A++++%5D%0A%7D
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这是$ _POST的var_dump的响应:
array(0) {
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}
这是$ _POST ['myData']的var_dump
NULL
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我对你使用contentType属性的方式持怀疑态度.尝试取出contentType.默认内容类型是application/x-www-form-urlencoded(http://api.jquery.com/jQuery.ajax/).
另外,为您的数据属性使用{mydata:jsontosend}之类的东西.
$.ajax({
type: "POST",
url: "process.php",
//contentType: "application/json; charset=utf-8",
dataType: "JSON",
data: {mydata: jsontosend},
success: function(msg){
alert(msg);
}
});
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