自我删除shell脚本

Question

我四处寻找这个问题的答案,却找不到答案.

我编写了一个简单的脚本来执行初始服务器设置,我希望它在完成时从根目录中删除/取消链接.我已经尝试了一些我用Google搜索的解决方案(例如/ bin/rm $ test.sh),但脚本似乎总是保持不变.这可能吗？下面是我的脚本到目前为止.

#! /bin/bash
cd /root/
wget -r -nH -np --cut-dirs=1 http://myhost.com/install/scripts/
rm -f index.html* *.gif */index.html* */*.gif robots.txt
ls -al /root/

if [ -d /usr/local/psa ]
    then
        echo plesk > /root/bin/INST_SERVER_TYPE.txt
    chmod 775 /root/bin/*
    /root/bin/setting_server_ve.sh
    rm -rf /root/etc | rm -rf /root/bin | rm -rf /root/log | rm -rf /root/old
    sed -i "75s/false/true/" /etc/permissions/jail.conf
        exit 1;
elif [ -d /var/webmin ]
    then
    echo webmin > /root/bin/INST_SERVER_TYPE.txt
    chmod 775 /root/bin/*
    /root/bin/setting_server_ve.sh
    rm -rf /root/etc | rm -rf /root/bin | rm -rf /root/log | rm -rf /root/old
    sed -i "67s/false/true/" /etc/permissions/jail.conf
        break
    exit 1;
else
    echo no-gui > /root/bin/INST_SERVER_TYPE.txt
    chmod 775 /root/bin/*
    /root/bin/setting_server_ve.sh
    rm -rf /root/etc | rm -rf /root/bin | rm -rf /root/log | rm -rf /root/old
    sed -i "67s/false/true/" /etc/permissions/jail.conf
        break
    exit 1;
fi  

Answer 1

rm -- "$0"

应该做的伎俩.$ 0是执行脚本的完整路径的魔术变量.

Answer 2

这对我有用:

#!/bin/sh

rm test.sh

也许你真的不想在'$ test.sh'中加上'$'？

Answer 3

脚本退出时可以通过shred 命令（作为安全删除）删除自身。

#!/bin/bash

currentscript="$0"

# Function that is called when the script exits:
function finish {
    echo "Securely shredding ${currentscript}"; shred -u ${currentscript};
}

# Do your bashing here...

# When your script is finished, exit with a call to the function, "finish":
trap finish EXIT