在下面的t-sql语句中,dbo.FUNC函数被调用多少次?
SELECT
column1,
column2,
dbo.FUNC(column3) AS column3
FROM table1
WHERE dbo.FUNC(column3) >= 5
ORDER BY dbo.FUNC(column3) DESC
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它会在每行调用多个单独的时间,还是优化器会识别出它在单个语句中被多次使用,并且只调用一次?
我该怎么测试呢?我无法插入函数内的表格,因此递增计数器不会工作...
Mar*_*ith 12
这不保证.
您需要检查执行计划以找出答案.一些例子.
CREATE FUNCTION dbo.FUNC1(@p1 int)
RETURNS int
AS
BEGIN
RETURN @p1 + 1
END
GO
CREATE FUNCTION dbo.FUNC2(@p1 int)
RETURNS int
WITH SCHEMABINDING
AS
BEGIN
RETURN @p1 + 1
END
GO
SELECT
OBJECTPROPERTYEX(OBJECT_ID('dbo.FUNC1'), 'IsDeterministic'),
OBJECTPROPERTYEX(OBJECT_ID('dbo.FUNC2'), 'IsDeterministic')
GO
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FUNC2已创建WITH SCHEMABINDING并被视为确定性.FUNC1不是.
SELECT
dbo.FUNC1(number) AS FUNC1,
dbo.FUNC2(number) AS FUNC2
FROM master..spt_values
WHERE dbo.FUNC1(number) >= 5 AND dbo.FUNC2(number) >= 5
ORDER BY dbo.FUNC1(number), dbo.FUNC2(number)
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给予计划

|--Sort(ORDER BY:([Expr1003] ASC, [Expr1004] ASC))
|--Compute Scalar(DEFINE:([Expr1003]=[test].[dbo].[FUNC1]([master].[dbo].[spt_values].[number])))
|--Filter(WHERE:([test].[dbo].[FUNC1]([master].[dbo].[spt_values].[number])>=(5) AND [Expr1004]>=(5)))
|--Compute Scalar(DEFINE:([Expr1004]=[test].[dbo].[FUNC2]([master].[dbo].[spt_values].[number])))
|--Index Scan(OBJECT:([master].[dbo].[spt_values].[ix2_spt_values_nu_nc]))
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FUNC1被评估两次(一次在过滤器中,一次在计算标量输出用于投影和排序的计算列),FUNC2仅评估一次.
重写为
SELECT
FUNC1,
FUNC2
FROM master..spt_values
CROSS APPLY (SELECT dbo.FUNC1(number), dbo.FUNC2(number)) C(FUNC1, FUNC2)
WHERE FUNC1 >= 5 AND FUNC2 >= 5
ORDER BY FUNC1, FUNC2
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略微更改计划,两者仅评估一次

|--Sort(ORDER BY:([Expr1003] ASC, [Expr1004] ASC))
|--Filter(WHERE:([Expr1003]>=(5)))
|--Compute Scalar(DEFINE:([Expr1003]=[test].[dbo].[FUNC1]([master].[dbo].[spt_values].[number])))
|--Filter(WHERE:([Expr1004]>=(5)))
|--Compute Scalar(DEFINE:([Expr1004]=[test].[dbo].[FUNC2]([master].[dbo].[spt_values].[number])))
|--Index Scan(OBJECT:([master].[dbo].[spt_values].[ix2_spt_values_nu_nc]))
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现在对查询稍作修改
SELECT
FUNC1 + 10,
FUNC2 + 10
FROM master..spt_values
CROSS APPLY (SELECT dbo.FUNC1(number), dbo.FUNC2(number)) C(FUNC1, FUNC2)
WHERE FUNC1 >= 5 AND FUNC2 >= 5
ORDER BY FUNC1, FUNC2
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给出与原始结果相反的结果,即FUNC2两次评估但FUNC1仅一次.

|--Compute Scalar(DEFINE:([Expr1005]=[Expr1003]+(10)))
|--Sort(ORDER BY:([Expr1003] ASC, [Expr1004] ASC))
|--Filter(WHERE:([Expr1003]>=(5)))
|--Compute Scalar(DEFINE:([Expr1003]=[test].[dbo].[FUNC1]([master].[dbo].[spt_values].[number])))
|--Filter(WHERE:([Expr1004]>=(5)))
|--Compute Scalar(DEFINE:([Expr1004]=[test].[dbo].[FUNC2]([master].[dbo].[spt_values].[number]), [Expr1006]=[test].[dbo].[FUNC2]([master].[dbo].[spt_values].[number])+(10)))
|--Index Scan(OBJECT:([master].[dbo].[spt_values].[ix2_spt_values_nu_nc]))
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