这是表
fid uid time
12 34 1
1 34 2
15 34 5
1 33 10
12 33 10
1 33 12
13 33 15
16 34 123
22 32 453
1 32 456
1 33 457
1 32 460
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现在我想计算每个uid地方的数量time is >9并且fid=1
喜欢这个
uid number of duplications
33 3
32 2
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SELECT uid, COUNT(*) FROM table WHERE fid=1 AND `time` > 9 GROUP BY uid
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