C#一起加入2个或更多课程？

Question

所以这可能听起来像一个n00b问题,但我想把2个类合并在一起.

像这样:

Ball oneBall = new Ball("red", 20);
Ball anotherBall = new Ball("blue",40);


Ball BigBall = new Ball(oneBall + anotherBall);

BigBall.size() //should say 60 right? 

我知道你会有这样的事情

class Ball{


  public Ball(string Name , int size){}

// But to merge to of them? 

  public Ball(Ball firstBall, Ball secondBall){} //I know the arguments have to be added
{}


} 

所以我的问题是什么是超载(对吧？)假设看起来像？

谢谢,

Answer 1

是的,您可以定义构造函数重载.

public class Ball
{
    public string Name { get; private set; }
    public int Size { get; private set; }

    public Ball(string name, int size) 
    { 
        this.Name = name;
        this.Size = size;
    }

    // This is called constructor chaining
    public Ball(Ball first, Ball second)
        : this(first.Name + "," + second.Name, first.Size + second.Size)
    { }
} 

合并两个球:

Ball bigBall = new Ball(oneBall, anotherBall);

请注意,您正在调用构造函数重载,而不是+运算符.

Answer 2

public class Ball
{
    public int Size { get; private set; }
    public string Name { get; private set; }

    public Ball(string name , int size)
    {
        Name = name;
        Size = size;
    }

    public Ball(Ball firstBall, Ball secondBall)
    {
        Name = firstBall.Name + ", " + secondBall.Name;
        Size = firstBall.Size + secondBall.Size;
    }
} 

Answer 3

您可能希望重载加法运算符Ball,例如:

public static Ball operator +(Ball left, Ball right)
{
    return new Ball(left.Name + right.Name, left.Size + right.Size);
}

虽然制作一个Ball接收2 Balls并添加它们的构造函数可能更具可读性,但如果你真的想写,new Ball(ball1 + ball2)那么运算符重载就可以了.如果您使用构造函数执行此操作,那么您的代码将如下所示:new Ball(ball1, ball2)