无法测试Symfony2控制台命令

jos*_*erk 4 php phpunit codesniffer symfony

作为学习Symfony2的一部分,我正在尝试编写一个非常简单的控制台命令,它只运行phpcs(PHP Code Sniffer).

这是执行函数,它在扩展ContainerAwareCommand的类中:

protected function execute(InputInterface $input, OutputInterface $output)
{
    $output->writeln('<info>Generating PHP Code Sniffer report...</info>');
    exec('phpcs ./src > ./app/logs/phpcs.log');

    if ($input->getOption('noprompt') == null) {
        $dialog = $this->getHelperSet()->get('dialog');
        if ($dialog->askConfirmation($output, '<question>Open report in TextMate? (y/n)?</question>', false)) {
            exec('mate ./app/logs/phpcs.log');
        }
    }

    $output->writeln('<info>...done</info>');
}
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我可以通过运行来执行控制台命令

app/console mynamespace:ci:phpcs
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它完美无缺.输出文件按预期生成.

我正在尝试使用以下函数(它是PHPUnit_Framework_TestCase的一部分)来测试mynamespace:ci:phpcs命令:

public function testExecute()
{
    $kernel = new \AppKernel("test", true);
    $kernel->boot();

    $application = new Application($kernel);
    $application->add(new PhpCodeSnifferCommand());

    $command = $application->find('mynamespace:ci:phpcs');
    $commandTester = new CommandTester($command);
    $commandTester->execute(array('command' => $command->getName()));

    // ... Test if output file was created here ... ommitted for brevity ... //
}
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但是,当尝试通过单元测试执行它时,它会失败并显示以下输出:

sh: phpcs: command not found
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有谁知道为什么会这样?

PS:我确实观察过的一件事是,当我在命令中注释掉调用'exec'的行时,测试会通过(不通过,但不会抱怨phpcs不存在),所以问题肯定是exec命令.

PHPUnit测试是作为不同的用户运行的,phpcs不可用吗?

Dav*_*ess 5

对于单元测试,你应该考虑模拟调用exec().这将加速您的测试并避免诸如此类的环境问题.对于这种情况,您可以简单地添加调用exec()您的类的方法,您可以模拟测试.

class PhpCodeSnifferCommand extends ...
{
    protected function execute(InputInterface $input, OutputInterface $output)
    {
        // ...
        runReport();
        // ...
                viewReport();
        // ...
    }

    protected function runReport() {
        exec('phpcs ./src > ./app/logs/phpcs.log');
    }

    protected function viewReport() {
        exec('mate ./app/logs/phpcs.log');
    }
}
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Mocking可以更轻松地验证三种可能的路径:

  1. 该命令被告知不提示用户查看报告.
  2. 命令被告知提示; 用户说没有.
  3. 命令被告知提示; 用户说是的.

将每个路径放在自己的测试中.您可以将公共代码放入测试助手方法中,以使其更短.

public function testRunsReportWithoutAskingToView()
{
    // ...

    $application = new Application($kernel);
    $phpcs = $this->getMock('PhpCodeSnifferCommand', array('runReport', 'viewReport'));
    $phpcs->expects($this->once())->method('runReport');
    $phpcs->expects($this->never())->method('viewReport');
    $application->add($phpcs);

    // Tell the command not to prompt to view the report ...
}

public function testRunsAndViewsReport()
{
    // ...

    $application = new Application($kernel);
    $phpcs = $this->getMock('PhpCodeSnifferCommand', array('runReport', 'viewReport'));
    $phpcs->expects($this->once())->method('runReport');
    $phpcs->expects($this->once())->method('viewReport');
    $application->add($phpcs);

    // Tell the command to prompt to view and the dialog to hit "Y" for you ...
}

public function testRunsReportButDoesntViewIt()
{
    // ...

    $application = new Application($kernel);
    $phpcs = $this->getMock('PhpCodeSnifferCommand', array('runReport', 'viewReport'));
    $phpcs->expects($this->once())->method('runReport');
    $phpcs->expects($this->never())->method('viewReport');
    $application->add($phpcs);

    // Tell the command to prompt to view and the dialog to hit "N" for you ...
}
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