cyr*_*usd 11 json ruby-on-rails respond-with
当从Rails 3.1应用程序返回包含"type"属性作为JSON的对象时,似乎不包括"type"属性.假设我有以下内容:
具有相应STI表Animal的模型.继承Animal的Cat,Dog和Fish模型.
通过JSON返回Animal时,我希望包含"type"列,但这不会发生:
jQuery.ajax("http://localhost:3001/animals/1", {dataType: "json"});
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收益率:
responseText: "{"can_swim":false,"created_at":"2012-01-20T17:55:16Z","id":1,"name":"Fluffy","updated_at":"2012-01-20T17:55:16Z","weight":9.0}"
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看来这是to_json的一个问题:
bash-3.2$ rails runner 'p Animal.first.to_yaml'
"--- !ruby/object:Cat\nattributes:\n id: 1\n type: Cat\n weight: 9.0\n name: Fluffy\n can_swim: false\n created_at: 2012-01-20 17:55:16.090646000 Z\n updated_at: 2012-01-20 17:55:16.090646000 Z\n"
bash-3.2$ rails runner 'p Animal.first.to_json'
"{\"can_swim\":false,\"created_at\":\"2012-01-20T17:55:16Z\",\"id\":1,\"name\":\"Fluffy\",\"updated_at\":\"2012-01-20T17:55:16Z\",\"weight\":9.0}"
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有谁知道这种行为背后的原因,以及如何覆盖它?
use*_*245 17
这就是我做的.它只是将缺失添加type到结果集中
def as_json(options={})
super(options.merge({:methods => :type}))
end
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覆盖as_json方法.它用于to_json产生输出.你可以这样做:
def as_json options={}
{
id: id,
can_swim: can_swim,
type: type
}
end
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