Man*_*lla 6 python plot gnuplot matplotlib
我有一组y值,形成一条线.另外,我有一个数组的元素数量与y数组的数量相同,范围从0到1.我们将这个数组称为'z'.我想绘制y值的数组,以便每个点的颜色对应于z值.
在gnuplot中,您可以使用'lc变量'来执行此操作:
plot ’data’ using 1:2:3 with points lc variable
Run Code Online (Sandbox Code Playgroud)
使用此处的建议:Matplotlib scatterplot; 颜色作为第三个变量的函数
,我能够使用散点图,它确实起作用:
import matplotlib as mpl
import matplotlib.pyplot as plt
plt.scatter(x, y, c=z, s=1, edgecolors='none', cmap=mpl.cm.jet)
plt.colorbar()
plt.show()
Run Code Online (Sandbox Code Playgroud)
有没有办法用matplotlib中的plot方法做到这一点,类似于这个?
plt.plot(x, y, c=z)
Run Code Online (Sandbox Code Playgroud)
当我尝试上面的代码时,所有的行都显示为黑色.
car*_*rla 17
我遇到了同样的问题:想要绘制具有非均匀颜色的线条,我希望它依赖于第三个变量(z).
但我确定想要使用一条线,而不是标记(如@ joaquin的回答).我在matplotlib库示例中找到了一个解决方案,使用了类matplotlib.collections.LineCollection(链接在这里).
这是我的示例,它绘制了底图中的轨迹,根据其高度对它们进行着色:
import matplotlib.pyplot as plt
from mpl_toolkits.basemap import Basemap
from matplotlib.collections import LineCollection
import numpy as np
m = Basemap(llcrnrlon=-42,llcrnrlat=0,urcrnrlon=5,urcrnrlat=50, resolution='h')
fig = plt.figure()
m.drawcoastlines()
m.drawcountries()
for i in trajectorias:
# for each i, the x (longitude), y (latitude) and z (height)
# are read from a file and stored as numpy arrays
points = np.array([x, y]).T.reshape(-1, 1, 2)
segments = np.concatenate([points[:-1], points[1:]], axis=1)
lc = LineCollection(segments, cmap=plt.get_cmap('Spectral'),
norm=plt.Normalize(250, 1500))
lc.set_array(z)
lc.set_linewidth(2)
plt.gca().add_collection(lc)
axcb = fig.colorbar(lc)
axcb.set_label('cota (m)')
plt.show()
Run Code Online (Sandbox Code Playgroud)

您可以使用分散:
plt.scatter(range(len(y)), y, c=z, cmap=cm.hot)
Run Code Online (Sandbox Code Playgroud)
这里有 ipython -pylab 会话:
In [27]: z = [0.3,0.4,0.5,0.6,0.7,0.2,0.3,0.4,0.5,0.8,0.9]
In [28]: y = [3, 7, 5, 6, 4, 8, 3, 4, 5, 2, 9]
In [29]: plt.scatter(range(len(y)), y, s=60, c=z, cmap=cm.hot)
Out[29]: <matplotlib.collections.PathCollection at 0x9ec8400>
Run Code Online (Sandbox Code Playgroud)

如果你想使用绘图,你可以使用(pycrust session)获得与上面相同的数字:
>>> from matplotlib import pyplot as plt
>>> from matplotlib import cm
>>> y = [3,7,5,6,4,8,3,4,5,2,9]
>>> z = [0.3,0.4,0.5,0.6,0.7,0.2,0.3,0.4,0.5,0.8,0.9]
>>> for x, (v, c) in enumerate(zip(y,z)):
... plt.plot(x,v,marker='o', color=cm.hot(c))
...
[<matplotlib.lines.Line2D object at 0x0000000008C42518>]
[<matplotlib.lines.Line2D object at 0x0000000008C426D8>]
[<matplotlib.lines.Line2D object at 0x0000000008C42B38>]
[<matplotlib.lines.Line2D object at 0x0000000008C452B0>]
[<matplotlib.lines.Line2D object at 0x0000000008C45438>]
[<matplotlib.lines.Line2D object at 0x0000000008C45898>]
[<matplotlib.lines.Line2D object at 0x0000000008C45CF8>]
[<matplotlib.lines.Line2D object at 0x0000000008C48198>]
[<matplotlib.lines.Line2D object at 0x0000000008C485F8>]
[<matplotlib.lines.Line2D object at 0x0000000008C48A58>]
[<matplotlib.lines.Line2D object at 0x0000000008C4B1D0>]
>>> plt.show()
>>>
Run Code Online (Sandbox Code Playgroud)