Dre*_*man 6 polymorphism inheritance jaxb eclipselink moxy
我正在使用MOXy的JAXB实现和外部元数据绑定文件来面对涉及继承和多态的编组/解组问题.
我无法控制XML文件或模型类.
模型中有多个继承其他DTO类的类.以下是我正在使用的环境示例.此示例仅用于某些语法目的,真实环境涉及嵌套继承,集合等.
这是将继承的类
class A {
private String name;
public String getName(){
return name;
}
public void setName(String value){
name = value;
}
}
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这是一个继承的类
class B extends A {
private String attrFromB;
public String getAttrFromB(){
return attrFromB;
}
public void setAttrFromB(String value){
attrFromB = value;
}
}
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而另一个
class C extends A {
private String attrFromC;
public String getAttrFromC(){
return attrFromC;
}
public void setAttrFromC(String value){
attrFromC= value;
}
}
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这是一个容器类
class MyContainerClass{
private A myObject;
public A getMyObject(){
return myObject;
}
public void setMyObject(A value){
myObject = value;
}
}
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这是在包含A的MyContainer的情况下应该生成的XML
<MyContainer>
<MyObject nameA="foo" />
</MyContainer>
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MyContainer包含B
<MyContainer>
<MyObject nameB="foo" attrFromB="bar" />
</MyContainer>
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而MyContainer包含C.
<MyContainer>
<MyObject nameC="foo" attrFromC="bar" />
</MyContainer>
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所以你已经可以看到地平线上的问题......
这是我要写的映射文件:
<?xml version="1.0"?>
<xml-bindings
xmlns="http://www.eclipse.org/eclipselink/xsds/persistence/oxm"
package-name="com.test.example"
version="2.1">
<java-type name="A" xml-accessor-type="NONE">
<xml-root-element name="MyObject" />
<java-attributes>
<xml-element java-attribute="name" xml-path="@nameA" />
</java-attributes>
</java-type>
<java-type name="B" xml-accessor-type="NONE">
<xml-root-element name="MyObject" />
<xml-see-also>
com.test.example.A
</xml.see.also>
<java-attributes>
<xml-element java-attribute="name" xml-path="@nameB" />
<xml-element java-attribute="attrFromB" xml-path="@attrFromB" />
</java-attributes>
</java-type>
<java-type name="C" xml-accessor-type="NONE">
<xml-root-element name="MyObject" />
<xml-see-also>
com.test.example.A
</xml.see.also>
<java-attributes>
<xml-element java-attribute="name" xml-path="@nameC" />
<xml-element java-attribute="attrFromC" xml-path="@attrFromC" />
</java-attributes>
</java-type>
<java-type name="MyContainer" xml-accessor-type="NONE">
<xml-root-element name="MyContainer" />
<java-attributes>
<xml-element java-attribute="myObject" type="com.test.example.A" xml-path="MyObject" />
</java-attributes>
</java-type>
</xml-bindings>
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第一个问题是,如果我绑定这样的类,我会得到以下异常:
[Exception [EclipseLink-44] (Eclipse Persistence Services - 2.3.0.v20110604-r9504): org.eclipse.persistence.exceptions.DescriptorException
Exception Description: Missing class indicator field from database row [UnmarshalRecord()].
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第一个问题:我理解这是正常的,Jaxb需要一些方法来确定MyContaioner.myObject属性的类型.问题是我无法访问传入的XML文件,所以我不能向它们添加xsi:type字段.有没有办法根据其中特定属性的存在来确定一个类?不管它的价值如何.如果源xml包含@attrFromC属性,我知道对象应该是C类型.如果它包含attrFromB,那么它是B.
第二个问题是B和C中不存在"name"属性,因此jaxb忽略了em.
--Ignoring attribute [name] on class [com.test.example.B] as no Property was generated for it.
--Ignoring attribute [name] on class [com.test.example.C] as no Property was generated for it.
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第二个问题:另一个问题是我不知道Jaxb是否能够覆盖XML文件中的xml属性名称(@ nameA,@ nameB和nameC都指向A.name),有没有办法做它?
在此先感谢您的时间.
以下是您的问题的答案。问题2的答案,也是问题1的答案。
第一个问题:我知道这是正常的,Jaxb 需要某种方法来确定 MyContainer.myObject 属性的类型。问题是我无权访问传入的 XML 文件,因此无法向其中添加 xsi:type 字段。有没有办法根据类中是否存在特定属性来确定类?不管它的价值。如果源 xml 包含 @attrFromC 属性,我知道该对象应该是 C 类型。如果它包含 attrFromB,则它是 B 类型。
对于此用例,您可以利用EclipseLink JAXB (MOXy)ClassExtractor
中的扩展:
我的类提取器
AClassExtractor
是一些代码,您可以实现这些代码来帮助 MOXy 确定应该实例化哪个类。系统会向您传递 a Record
,您可以通过 XPath 询问当前元素中是否存在属性,以确定应实例化哪个类。
package com.test.example;
import org.eclipse.persistence.descriptors.ClassExtractor;
import org.eclipse.persistence.sessions.*;
public class MyClassExtractor extends ClassExtractor{
@Override
public Class<?> extractClassFromRow(Record record, Session session) {
if(null != record.get("@attrFromB")) {
return B.class;
} else if(null != record.get("@attrFromC")) {
return C.class;
} else {
return A.class;
}
}
}
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元数据 (oxm.xml)
您可以ClassExtractor
使用@XmlClassExtractor
注释进行配置。您还可以通过外部元数据文件来执行此操作。我已对您的问题中包含的内容进行了调整,以包括以下内容:
<?xml version="1.0"?>
<xml-bindings
xmlns="http://www.eclipse.org/eclipselink/xsds/persistence/oxm"
package-name="com.test.example"
version="2.3">
<java-types>
<java-type name="A" xml-accessor-type="NONE">
<xml-class-extractor class="com.test.example.MyClassExtractor"/>
<xml-root-element name="MyObject" />
<java-attributes>
<xml-attribute java-attribute="name" name="nameA" />
</java-attributes>
</java-type>
<java-type name="B" xml-accessor-type="NONE">
<xml-root-element name="MyObject" />
<java-attributes>
<xml-attribute java-attribute="name" name="nameB" />
<xml-attribute java-attribute="attrFromB"/>
</java-attributes>
</java-type>
<java-type name="C" xml-accessor-type="NONE">
<xml-root-element name="MyObject" />
<java-attributes>
<xml-attribute java-attribute="name" name="nameC" />
<xml-attribute java-attribute="attrFromC"/>
</java-attributes>
</java-type>
<java-type name="MyContainerClass" xml-accessor-type="NONE">
<xml-root-element name="MyContainer" />
<java-attributes>
<xml-element java-attribute="myObject" name="MyObject" />
</java-attributes>
</java-type>
</java-types>
</xml-bindings>
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演示
以下演示代码对您的问题中的每个 XML 文档进行解组,并输出该属性所持有的类型myObject
:
package com.test.example;
import java.io.StringReader;
import java.util.*;
import javax.xml.bind.*;
import org.eclipse.persistence.jaxb.JAXBContextFactory;
public class Demo {
public static void main(String[] args) throws Exception {
Map<String, Object> properties = new HashMap<String, Object>();
properties.put(JAXBContextFactory.ECLIPSELINK_OXM_XML_KEY, "com/test/example/oxm.xml");
JAXBContext jc = JAXBContext.newInstance(new Class[] {MyContainerClass.class}, properties);
Unmarshaller unmarshaller = jc.createUnmarshaller();
StringReader aXml = new StringReader("<MyContainer><MyObject nameA='foo'/></MyContainer>");
MyContainerClass myContainerA = (MyContainerClass) unmarshaller.unmarshal(aXml);
System.out.println(myContainerA.getMyObject().getClass());
StringReader bXml = new StringReader("<MyContainer><MyObject nameB='foo' attrFromB='bar'/></MyContainer>");
MyContainerClass myContainerB = (MyContainerClass) unmarshaller.unmarshal(bXml);
System.out.println(myContainerB.getMyObject().getClass());
StringReader cXml = new StringReader("<MyContainer><MyObject nameC='foo' attrFromC='bar'/></MyContainer>");
MyContainerClass myContainerC = (MyContainerClass) unmarshaller.unmarshal(cXml);
System.out.println(myContainerC.getMyObject().getClass());
}
}
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输出
[EL Warning]: 2012-01-20 10:36:41.828--Ignoring attribute [name] on class [com.test.example.B] as no Property was generated for it.
[EL Warning]: 2012-01-20 10:36:41.828--Ignoring attribute [name] on class [com.test.example.C] as no Property was generated for it.
class com.test.example.A
class com.test.example.B
class com.test.example.C
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第二个问题:另一个问题是我不知道 Jaxb 是否能够像 XML 文件中所期望的那样覆盖 xml 属性名称(@nameA、@nameB 和 nameC 均指 A.name),有没有办法做到它 ?
您可以利用 anXmlAdapter
来回答这个问题。这种方法也可以用来回答你的第一个问题:
适配器
package com.test.example;
import javax.xml.bind.annotation.XmlAttribute;
import javax.xml.bind.annotation.adapters.XmlAdapter;
public class AAdapter extends XmlAdapter<AAdapter.AdaptedA, A> {
@Override
public AdaptedA marshal(A a) throws Exception {
if(null == a) {
return null;
}
AdaptedA adaptedA = new AdaptedA();
if(a instanceof C) {
C c = (C) a;
adaptedA.nameC = c.getName();
adaptedA.attrFromC = c.getAttrFromC();
} else if(a instanceof B) {
B b = (B) a;
adaptedA.nameB = b.getName();
adaptedA.attrFromB = b.getAttrFromB();
} else if(a instanceof A) {
adaptedA.nameA = a.getName();
}
return adaptedA;
}
@Override
public A unmarshal(AdaptedA adaptedA) throws Exception {
if(null == adaptedA) {
return null;
}
if(null != adaptedA.attrFromC) {
C c = new C();
c.setName(adaptedA.nameC);
c.setAttrFromC(adaptedA.attrFromC);
return c;
} else if(null != adaptedA.attrFromB) {
B b = new B();
b.setName(adaptedA.nameB);
b.setAttrFromB(adaptedA.attrFromB);
return b;
}
A a = new A();
a.setName(adaptedA.nameA);
return a;
}
public static class AdaptedA {
@XmlAttribute public String nameA;
@XmlAttribute public String nameB;
@XmlAttribute public String nameC;
@XmlAttribute public String attrFromB;
@XmlAttribute public String attrFromC;
}
}
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元数据 (oxm-2.xml)
<?xml version="1.0"?>
<xml-bindings
xmlns="http://www.eclipse.org/eclipselink/xsds/persistence/oxm"
package-name="com.test.example"
version="2.3">
<java-types>
<java-type name="MyContainerClass" xml-accessor-type="NONE">
<xml-root-element name="MyContainer" />
<java-attributes>
<xml-element java-attribute="myObject" name="MyObject">
<xml-java-type-adapter value="com.test.example.AAdapter"/>
</xml-element>
</java-attributes>
</java-type>
</java-types>
</xml-bindings>
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演示2
package com.test.example;
import java.io.StringReader;
import java.util.*;
import javax.xml.bind.*;
import org.eclipse.persistence.jaxb.JAXBContextFactory;
public class Demo2 {
public static void main(String[] args) throws Exception {
Map<String, Object> properties = new HashMap<String, Object>();
properties.put(JAXBContextFactory.ECLIPSELINK_OXM_XML_KEY, "com/test/example/oxm-2.xml");
JAXBContext jc = JAXBContext.newInstance(new Class[] {MyContainerClass.class}, properties);
Unmarshaller unmarshaller = jc.createUnmarshaller();
Marshaller marshaller = jc.createMarshaller();
marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
StringReader aXml = new StringReader("<MyContainer><MyObject nameA='foo'/></MyContainer>");
MyContainerClass myContainerA = (MyContainerClass) unmarshaller.unmarshal(aXml);
System.out.println(myContainerA.getMyObject().getClass());
marshaller.marshal(myContainerA, System.out);
StringReader bXml = new StringReader("<MyContainer><MyObject nameB='foo' attrFromB='bar'/></MyContainer>");
MyContainerClass myContainerB = (MyContainerClass) unmarshaller.unmarshal(bXml);
System.out.println(myContainerB.getMyObject().getClass());
marshaller.marshal(myContainerB, System.out);
StringReader cXml = new StringReader("<MyContainer><MyObject nameC='foo' attrFromC='bar'/></MyContainer>");
MyContainerClass myContainerC = (MyContainerClass) unmarshaller.unmarshal(cXml);
System.out.println(myContainerC.getMyObject().getClass());
marshaller.marshal(myContainerC, System.out);
}
}
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输出
class com.test.example.A
<?xml version="1.0" encoding="UTF-8"?>
<MyContainer>
<MyObject nameA="foo"/>
</MyContainer>
class com.test.example.B
<?xml version="1.0" encoding="UTF-8"?>
<MyContainer>
<MyObject nameB="foo" attrFromB="bar"/>
</MyContainer>
class com.test.example.C
<?xml version="1.0" encoding="UTF-8"?>
<MyContainer>
<MyObject nameC="foo" attrFromC="bar"/>
</MyContainer>
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