Bat*_*man 24 spring web.xml spring-mvc dispatcher
我正在尝试创建一个简单的Spring 3应用程序并具有以下文件.请告诉我这个错误的原因
下面是我的web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
id="WebApp_ID" version="3.0">
<display-name>Spring2</display-name>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>0</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
下面是我的index.jsp
<%@ page language="java" contentType="text/html; charset=ISO-8859-1" pageEncoding="ISO-8859-1"%>
<%@ taglib prefix="form" uri="http://www.springframework.org/tags/form" %>
<%@ taglib prefix="spring" uri="http://www.springframework.org/tags" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
Index Page<br/>
<form:form commandName="loginBean" method="POST" action="login">
<form:input path="userName" id="userName"/><br/>
<form:input path="password" id="password"/><br/>
<input type="submit" value="submit"/>
</form:form>
<a href="register.jsp">Go to Registration Page</a>
</body>
</html>
下面是我的dispatcher-servlet.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd">
<bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/" />
<property name="suffix" value=".jsp" />
</bean>
<bean name="/login" class="com.infy.controller.LoginController"/>
</beans>
这是LoginController.java
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.ModelAttribute;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;
@Controller
public class LoginController {
@RequestMapping(value="/login", method=RequestMethod.POST)
public ModelAndView loginAction(@ModelAttribute("loginBean")LoginBean bean){
return new ModelAndView("success", "success", "Successful Login");
}
}
最后是我的LoginBean
public class LoginBean {
private String userName;
private String password;
public String getUserName() {
return userName;
}
public void setUserName(String userName) {
this.userName = userName;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
}
Ara*_*d A 71
您必须在web.xml中安装ContextLoaderListener - 它会加载您的配置文件.
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
您需要了解Web应用程序上下文和根应用程序上下文之间的区别.
在Web MVC框架中,每个DispatcherServlet都有自己的WebApplicationContext,它继承了根WebApplicationContext中已定义的所有bean.定义的这些继承bean可以在特定于servlet的作用域中重写,并且可以在给定servlet实例的本地定义新的作用域特定bean.
调度程序servlet的应用程序上下文是一个Web应用程序上下文,仅适用于Web类.您不能将这些用于中间层.这些需要使用ContextLoaderListener的全局应用程序上下文.
阅读Spring参考这里的Spring MVC的.
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