And*_*ein 18
没有多少添加到@Phonon和@dantswain的答案,只是范围[a-Z],[A-Z]可以在更痛苦的方式产生,并且randi可以用来创建整数随机值.
symbols = ['a':'z' 'A':'Z' '0':'9'];
MAX_ST_LENGTH = 50;
stLength = randi(MAX_ST_LENGTH);
nums = randi(numel(symbols),[1 stLength]);
st = symbols (nums);
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这应该工作
s = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789'; %find number of random characters to choose from numRands = length(s); %specify length of random string to generate sLength = 50; %generate random string randString = s( ceil(rand(1,sLength)*numRands) )
在我意识到你想要[AZ] [az]和[0-9]之前我开始写这个.为此,@ Phonon的答案很好.
作为替代方案,这将在从空格(32)到波浪号(126)的所有可读字符中生成随机ASCII字符:
length = 10;
random_string = char(floor(94*rand(1, length)) + 32);
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