Bas*_*sit 0 javascript jquery html-table jquery-selectors
我有一张桌子tr和td.我td有一个div孩子.其中div有id="question"和另一个有id="answer".我想,在遍历我td时,div有id="answer"被隐藏.页面加载时,只会div出现问题.这是html的结构
<td style="display: none;">
<div style="border-color: #000000;position: relative;float: right;margin-top: 2px;right: 12%;"> </div>
<div style="border-color: #000000;position: relative;float: right;margin-top: 2px;right:-2%;"> </div>
<div id="question">
<img id="faqGrid:0:j_idt77" height="10" width="480" src="/TDAP/faces/javax.faces.resource/spacer/dot_clear.gif?ln=primefaces&v=2.2.RC2">
<br>
<br>
<div id="answer">
<div class="horizontalline"></div>
</td>
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我做了以下.但它隐藏了整个td.
$('#faqGrid tr td').each(function(){
var $cells = $();
/**
*Gives you all children as an object array
* 0: div
* 1: div
* 2: div#question
* 3: img#faqGrid:0:j_idt77 /TDAP/fa...=2.2.RC2
* 4: br
* 5: br
* 6: div#answer
* 7: div.horizontalline
*/
var tdChildrenArray = $(this).children();
var divChildrenArray = $(this).children('div');
var elementStack;
$.each(divChildrenArray, function(index, value){
var $div = value;
if ($div.id) {
var $divId = $div.id;
if ($divId == 'answer') {
var colNum = $(this).cellIndex;
$cells = $cells.add($div);
} //end of if ($divId == 'answer')
} //end of if ($div.id)
}); //end of $.each(object, fn)
return $(this).pushStack($cells);
}).hide(); //end of $('#faqGrid tr td').each(fn)
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我的想法是,div推送栈上的那些只应隐藏,但这不是真正的输出.
如果您有多行,则不应使用多个ID属性.改为将其更改为班级......
<div class="question">
<img id="faqGrid:0:j_idt77" height="10" width="480" src="/TDAP/faces/javax.faces.resource/spacer/dot_clear.gif?ln=primefaces&v=2.2.RC2">
<br>
<br>
<div class="answer">
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然后你可以做这个简单的JQuery来隐藏答案元素......
$(".answer").hide();
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要直接回答您的问题,.hide()无论如何,您将被称为TD元素集合上的函数.
你可以.hide()从最后移动并放入这条线......
if ($divId == 'answer') {
$div.hide();//hide your answer element
var colNum = $(this).cellIndex;
$cells = $cells.add($div);
} //end of if ($divId == 'answer')
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...但这是很简单的代码
编辑:您可能尝试做的一个示例