SQL Server:提取表元数据(描述,字段及其数据类型)

Question

我试图找到一种方法来提取有关SQL Server(2008)中的表的信息.
我需要的数据需要包括表的描述(从属性窗口的Description属性填充),该表的字段列表及其各自的数据类型.

有什么方法可以提取这样的元数据吗？我认为我必须使用一些syssp,但我不确定是哪一个.

Answer 1

为了获取描述数据,您遗憾的是必须使用sysobjects/syscolumns来获取ID:

SELECT      u.name + '.' + t.name AS [table],
            td.value AS [table_desc],
            c.name AS [column],
            cd.value AS [column_desc]
FROM        sysobjects t
INNER JOIN  sysusers u
    ON      u.uid = t.uid
LEFT OUTER JOIN sys.extended_properties td
    ON      td.major_id = t.id
    AND     td.minor_id = 0
    AND     td.name = 'MS_Description'
INNER JOIN  syscolumns c
    ON      c.id = t.id
LEFT OUTER JOIN sys.extended_properties cd
    ON      cd.major_id = c.id
    AND     cd.minor_id = c.colid
    AND     cd.name = 'MS_Description'
WHERE t.type = 'u'
ORDER BY    t.name, c.colorder

你可以用info-schema来做,但你必须连接等来调用OBJECT_ID() - 那么重点是什么？

Answer 2

有关表和列的一般信息可以在这些表中找到:

select * from INFORMATION_SCHEMA.TABLES
select * from INFORMATION_SCHEMA.COLUMNS

表描述是扩展属性,您可以从sys.extended_properties中查询它们:

select 
    TableName = tbl.table_schema + '.' + tbl.table_name, 
    TableDescription = prop.value,
    ColumnName = col.column_name, 
    ColumnDataType = col.data_type
FROM information_schema.tables tbl
INNER JOIN information_schema.columns col 
    ON col.table_name = tbl.table_name
    AND col.table_schema = tbl.table_schema
LEFT JOIN sys.extended_properties prop 
    ON prop.major_id = object_id(tbl.table_schema + '.' + tbl.table_name) 
    AND prop.minor_id = 0
    AND prop.name = 'MS_Description' 
WHERE tbl.table_type = 'base table'

Answer 3

你可以试试 sp_help <Name of object>

Answer 4

我最喜欢@Andomar的答案,但我也需要列描述.这是他的查询修改,以包括那些.(取消注释WHERE子句的最后一部分,仅返回其中描述为非null的行).

SELECT
    TableName = tbl.table_schema + '.' + tbl.table_name, 
    TableDescription = tableProp.value,
    ColumnName = col.column_name, 
    ColumnDataType = col.data_type,
    ColumnDescription = colDesc.ColumnDescription
FROM information_schema.tables tbl
INNER JOIN information_schema.columns col 
    ON col.table_name = tbl.table_name
LEFT JOIN sys.extended_properties tableProp 
    ON tableProp.major_id = object_id(tbl.table_schema + '.' + tbl.table_name) 
        AND tableProp.minor_id = 0
        AND tableProp.name = 'MS_Description' 
LEFT JOIN (
    SELECT sc.object_id, sc.column_id, sc.name, colProp.[value] AS ColumnDescription
    FROM sys.columns sc
    INNER JOIN sys.extended_properties colProp
        ON colProp.major_id = sc.object_id
            AND colProp.minor_id = sc.column_id
            AND colProp.name = 'MS_Description' 
) colDesc
    ON colDesc.object_id = object_id(tbl.table_schema + '.' + tbl.table_name)
        AND colDesc.name = col.COLUMN_NAME
WHERE tbl.table_type = 'base table'
--AND tableProp.[value] IS NOT NULL OR colDesc.ColumnDescription IS NOT null

Answer 5

使用对象目录视图:

SELECT  T.NAME AS [TABLE NAME], C.NAME AS [COLUMN NAME], P.NAME AS [DATA TYPE], P.MAX_LENGTH AS[SIZE],   CAST(P.PRECISION AS VARCHAR) +‘/’+ CAST(P.SCALE AS VARCHAR) AS [PRECISION/SCALE]
FROM ADVENTUREWORKS.SYS.OBJECTS AS T
JOIN ADVENTUREWORKS.SYS.COLUMNS AS C
ON T.OBJECT_ID=C.OBJECT_ID
JOIN ADVENTUREWORKS.SYS.TYPES AS P
ON C.SYSTEM_TYPE_ID=P.SYSTEM_TYPE_ID
WHERE T.TYPE_DESC=‘USER_TABLE’;

使用信息架构视图

SELECT TABLE_SCHEMA, TABLE_NAME, COLUMN_NAME, ORDINAL_POSITION,
       COLUMN_DEFAULT, DATA_TYPE, CHARACTER_MAXIMUM_LENGTH,
       NUMERIC_PRECISION, NUMERIC_PRECISION_RADIX, NUMERIC_SCALE,
       DATETIME_PRECISION
FROM ADVENTUREWORKS.INFORMATION_SCHEMA.COLUMNS

Answer 6

看一下这个：

SELECT TABLE_SCHEMA ,
       TABLE_NAME ,
       COLUMN_NAME ,
       ORDINAL_POSITION ,
       COLUMN_DEFAULT ,
       DATA_TYPE ,
       CHARACTER_MAXIMUM_LENGTH ,
       NUMERIC_PRECISION ,
       NUMERIC_PRECISION_RADIX ,
       NUMERIC_SCALE ,
       DATETIME_PRECISION
FROM   INFORMATION_SCHEMA.COLUMNS
where TABLE_SCHEMA in ('dbo','meta')
and table_name in (select name from sys.tables)
order by TABLE_SCHEMA ,       TABLE_NAME ,ORDINAL_POSITION