VB6似乎不容易将+无穷大,无穷大和NaN存储到双变量中.如果可以的话,我可以在复杂数字的背景下与这些值进行比较.怎么样?
Yog*_*uno 19
实际上,有一种更简单的方法来获得Infinity,-Infinity而不是数字:
public lfNaN as Double ' or As Single
public lfPosInf as Double
public lfNegInf as Double
on error resume next ' to ignore Run-time error '6': Overflow and '11': Division by zero
lfNaN = 0 / 0 ' -1.#IND
lfPosInf = 1 / 0 ' 1.#INF
lfNegInf = -1 / 0 ' -1.#INF
on error goto 0 ' optional to reset the error handler
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Oor*_*ang 13
一些不同的东西.从Pax的示例中可以看出,您只需要查找IEEE 754标准,然后将字节插入正确的位置.我要给你的唯一警告是MicroSoft已弃用RtlMoveMemory,因为它可能会产生溢出类型的安全问题.作为替代方案,您可以使用用户定义类型和LSet通过一点谨慎的强制在"纯"VB中完成此操作.(另请注意,有两种类型的NaN.)
Option Explicit
Public Enum abIEEE754SpecialValues
abInfinityPos
abInfinityNeg
abNaNQuiet
abNaNSignalling
abDoubleMax
abDoubleMin
End Enum
Private Type TypedDouble
value As Double
End Type
Private Type ByteDouble
value(7) As Byte
End Type
Public Sub Example()
MsgBox GetIEEE754SpecialValue(abDoubleMax)
End Sub
Public Function GetIEEE754SpecialValue(ByVal value As abIEEE754SpecialValues) As Double
Dim dblRtnVal As Double
Select Case value
Case abIEEE754SpecialValues.abInfinityPos
dblRtnVal = BuildDouble(byt6:=240, byt7:=127)
Case abIEEE754SpecialValues.abInfinityNeg
dblRtnVal = BuildDouble(byt6:=240, byt7:=255)
Case abIEEE754SpecialValues.abNaNQuiet
dblRtnVal = BuildDouble(byt6:=255, byt7:=255)
Case abIEEE754SpecialValues.abNaNSignalling
dblRtnVal = BuildDouble(byt6:=248, byt7:=255)
Case abIEEE754SpecialValues.abDoubleMax
dblRtnVal = BuildDouble(255, 255, 255, 255, 255, 255, 239, 127)
Case abIEEE754SpecialValues.abDoubleMin
dblRtnVal = BuildDouble(255, 255, 255, 255, 255, 255, 239, 255)
End Select
GetIEEE754SpecialValue = dblRtnVal
End Function
Public Function BuildDouble( _
Optional byt0 As Byte = 0, _
Optional byt1 As Byte = 0, _
Optional byt2 As Byte = 0, _
Optional byt3 As Byte = 0, _
Optional byt4 As Byte = 0, _
Optional byt5 As Byte = 0, _
Optional byt6 As Byte = 0, _
Optional byt7 As Byte = 0 _
) As Double
Dim bdTmp As ByteDouble, tdRtnVal As TypedDouble
bdTmp.value(0) = byt0
bdTmp.value(1) = byt1
bdTmp.value(2) = byt2
bdTmp.value(3) = byt3
bdTmp.value(4) = byt4
bdTmp.value(5) = byt5
bdTmp.value(6) = byt6
bdTmp.value(7) = byt7
LSet tdRtnVal = bdTmp
BuildDouble = tdRtnVal.value
End Function
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最后一点,你也可以这样得到NaN:
Public Function GetNaN() As Double
On Error Resume Next
GetNaN = 0 / 0
End Function
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