使用php中的opendir()按字母顺序排序和显示目录列表

Question

php noob here - 我拼凑了这个脚本来显示一个带有opendir的文件夹中的图像列表,但我无法弄清楚如何(或在哪里)按字母顺序对数组进行排序

<?php

// opens images folder
if ($handle = opendir('Images')) {
while (false !== ($file = readdir($handle))) {

// strips files extensions  
$crap   = array(".jpg", ".jpeg", ".JPG", ".JPEG", ".png", ".PNG", ".gif", ".GIF", ".bmp", ".BMP", "_", "-");    

$newstring = str_replace($crap, " ", $file );   

//asort($file, SORT_NUMERIC); - doesnt work :(

// hides folders, writes out ul of images and thumbnails from two folders

    if ($file != "." && $file != ".." && $file != "index.php" && $file != "Thumbnails") {
    echo "<li><a href=\"Images/$file\" class=\"thickbox\" rel=\"gallery\" title=\"$newstring\"><img src=\"Images/Thumbnails/$file\" alt=\"$newstring\" width=\"300\"  </a></li>\n";}
}
closedir($handle);
}

?>

任何建议或指示将不胜感激!

Answer 1

在对文件进行排序之前,需要先将文件读入数组.这个怎么样？

<?php
$dirFiles = array();
// opens images folder
if ($handle = opendir('Images')) {
    while (false !== ($file = readdir($handle))) {

        // strips files extensions      
        $crap   = array(".jpg", ".jpeg", ".JPG", ".JPEG", ".png", ".PNG", ".gif", ".GIF", ".bmp", ".BMP", "_", "-");    

        $newstring = str_replace($crap, " ", $file );   

        //asort($file, SORT_NUMERIC); - doesnt work :(

        // hides folders, writes out ul of images and thumbnails from two folders

        if ($file != "." && $file != ".." && $file != "index.php" && $file != "Thumbnails") {
            $dirFiles[] = $file;
        }
    }
    closedir($handle);
}

sort($dirFiles);
foreach($dirFiles as $file)
{
    echo "<li><a href=\"Images/$file\" class=\"thickbox\" rel=\"gallery\" title=\"$newstring\"><img src=\"Images/Thumbnails/$file\" alt=\"$newstring\" width=\"300\"  </a></li>\n";
}

?>

编辑:这与您要求的内容无关,但您也可以通过pathinfo()函数获得更通用的文件扩展名处理.您不需要硬编码的扩展数组,您可以删除任何扩展名.

Answer 2

运用 opendir()

opendir()不允许对列表进行排序.您必须手动执行排序.为此,首先将所有文件名添加到数组中,然后使用sort()以下内容对它们进行排序:

$path = "/path/to/file";

if ($handle = opendir($path)) {
    $files = array();
    while ($files[] = readdir($dir));
    sort($files);
    closedir($handle);
}

并随后用一一列举foreach:

$blacklist = array('.','..','somedir','somefile.php');

foreach ($files as $file) {
    if (!in_array($file, $blacklist)) {
        echo "<li>$file</a>\n <ul class=\"sub\">";
    }
}

运用 scandir()

使用起来容易得多scandir().它默认为您执行排序.使用以下代码可以实现相同的功能:

$path = "/path/to/file";
$blacklist = array('somedir','somefile.php');

// get everything except hidden files
$files = preg_grep('/^([^.])/', scandir($path)); 

foreach ($files as $file) {
    if (!in_array($file, $blacklist)) {
        echo "<li>$file</a>\n <ul class=\"sub\">";
    }
}

使用DirectoryIterator(首选)

$path = "/path/to/file";
$blacklist = array('somedir','somefile.php');

foreach (new DirectoryIterator($path) as $fileInfo) {
    if($fileInfo->isDot()) continue;
    $file =  $path.$fileInfo->getFilename();
    echo "<li>$file</a>\n <ul class=\"sub\">";
}