use*_*103 2 c# asp.net drop-down-menu
当我在下拉列表中选择一个值时,我得到一个回发,即使在回发后也选择了我选择的值.如何在回发后再次获取默认值< - 选择城市 - >作为选定值?
HTML:
<asp:DropDownList ID="ddlCity" Width="200px" runat="server" AutoPostBack="true"
OnSelectedIndexChanged="ddlCity_SelectedIndexChanged"> </asp:DropDownList>
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标记:
protected void Page_Load(object sender, EventArgs e)
{
DataTable CityMembersTable = GetCity();
ddlCity.DataSource = CityMembersTable;
ddlCity.DataTextField = "CityName";
ddlCity.DataValueField = "CityID";
ddlCity.DataBind();
ddlCity.Items.Insert(0, new ListItem("<--Choose City-->", ""));
}
protected void ddlCity_SelectedIndexChanged(object sender, EventArgs e)
{
if (ddlCity.SelectedValue == "")
{
return;
}
ddlCity.SelectedValue == "0"; //Dose not work...
}
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您需要首先处理IsPostBack页面加载,因为您在页面加载时绑定下拉列表.此外,如果您的if条件执行,ddlCity.SelectedValue == "0";将不会执行.
protected void Page_Load(object sender, EventArgs e)
{
if(Page.IsPostBack == false)
{
DataTable CityMembersTable = GetCity();
ddlCity.DataSource = CityMembersTable;
ddlCity.DataTextField = "CityName";
ddlCity.DataValueField = "CityID";
ddlCity.DataBind();
ddlCity.Items.Insert(0, new ListItem("<--Choose City-->", ""));
}
}
protected void ddlCity_SelectedIndexChanged(object sender, EventArgs e)
{
ddlCity.SelectedIndex = 0; //Put this here
if (ddlCity.SelectedValue == "")
{
return;
}
}
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