Hibernate一对一,没有给定标识符的行存在异常

Question

我需要两个实体之间的链接,所以我使用一对一

@Entity
@Table(name = "T_USER")
public class User implements Serializable {

    @Id
    @Column(name = "user_id")
    private int userId;

    @Column(name = "login")
    private String login;

    @OneToOne(optional = true)    
    @JoinColumn(name="login", referencedColumnName="person_id", nullable = true, insertable = false, updatable = false)
    private Person person;
}

@Entity
@Table(name = "T_PERSON")
public class Person implements Serializable {
    @Id
    @Column(name = "person_id")
    private String personId;

    @Column(name = "pin")
    private String pin;
}

如果表T_USER中没有特定PERSON的项,user.getPerson会抛出异常:

org.hibernate.ObjectNotFoundException: No row with the given identifier exists: [packagename.com.entity.Person#scabriou]

但是如果我在db中的两个表之间有引用,那么getter就可以了!

Answer 1

我不能说这是否是最好的解决方案,但你可以使用@NotFound注释.例如

@NotFound(action = NotFoundAction.IGNORE)
private Person person;

我相信人会留下来null,不会抛出异常.