我一直在学习Clojure并对以下内容感到困惑:
user=> (for [a (range 1 4) b (range 1 4)] [a b])
([1 1] [1 2] [1 3] [2 1] [2 2] [2 3] [3 1] [3 2] [3 3]); _no surprise here_
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让我们添加:while (not= a b)
,我希望看到一个空列表,因为如果条件为假,循环应该停止.在这种情况下,它是a
= b
= 1的第一个项目.让我们来看看:
user=> (for [a (range 1 4) b (range 1 4) :while (not= a b) ] [a b])
([2 1] [3 1] [3 2]) ; _surprise!_
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改变:while
以:when
过滤掉(= a b)
对
user=> (for [a (range 1 4) b (range 1 4) :when (not= a b) ] [a b])
([1 2] [1 3] [2 1] [2 3] [3 1] [3 2]); _expected_
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任何人都可以解释为什么(for [ ... :while ..] ...)
会这样吗?
我在OS X上使用Clojure 1.3.
谢谢你,并为缺乏格式而道歉.这是我在StackOverflow上的处女帖子.
让我们看看每次迭代.
a = 1
b = 1 -> a == b, break because of while
a = 2
b = 1 -> a != b, print [2 1]
b = 2 -> a == b, break because of while
a = 3
b = 1 -> a != b, print [3 1]
b = 2 -> a != b, print [3 2]
b = 3 -> a == b, break because of while
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