Jor*_*man 9 javascript jquery jquery-ui
我正在使用jquery/javascript处理这个拖放应用程序,我必须使用两者之间的平衡来完成我想要的.
var drop = document.elementFromPoint($(this).offset().left, $(this).offset().top);
这里我想用这个代码做的是获取我的draggable试图被丢弃的元素(目前正在盘旋).但是,这将始终返回我的draggable,而不是td它下面的table cell().
因为我知道我在寻找一个td元素,有没有办法设置var drop为:
var drop = document.elementFromPoint(x, y, 'td')?
或者有更好的方法来做这件事吗?
Ker*_*Liu 16
由于document.elementFromPoint返回最顶层元素,您需要暂时将可拖动设置为display:none或pointer-events:none在其下方查找元素.我在下面创建了一个要点,它返回给定点上所有元素的列表.
尝试
var elementsArray = KoreSampl.atPoint(x,y,yourTableElement);
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要么
var elementsArray = KoreSampl.fromEvent(dropEvent, yourTableElement);
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然后
for(var i=0; i<elementsArray.length; i++) {
//loop through elementsArray until you find the td you're interested in
}
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使用下面的要点:https://gist.github.com/2166393
;(function(){
//test for ie: turn on conditional comments
var jscript/*@cc_on=@_jscript_version@*/;
var styleProp = (jscript) ? "display" : "pointerEvents";
var KoreSampl = function() {};
KoreSampl.prototype.fromEvent = function(e, lastElement) {
e = e || window.event; //IE for window.event
return this.atPoint(e.clientX, e.clientY, lastElement);
};
KoreSampl.prototype.atPoint = function(clientX, clientY, lastElement) {
//support for child iframes
var d = (lastElement) ? lastElement.ownerDocument : document;
//the last element in the list
lastElement = lastElement || d.getElementsByTagName("html")[0];
var element = d.elementFromPoint(clientX, clientY);
if(element === lastElement || element.nodeName === "HTML") {
return [element];
} else {
var style= element.style[styleProp];
element.style[styleProp]="none"; //let us peak at the next layer
var result = [element].concat(this.atPoint(clientX,clientY,lastElement));
element.style[styleProp]= style; //restore
return result;
}
};
window["KoreSampl"] = new KoreSampl();
})();
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如果您可以省去旧浏览器,以下CSS将起作用:
只需将此规则应用于您正在拖动的最顶层元素即可.
#dragging {
pointer-events: none;
}
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