Ata*_*ang 4 activerecord join ruby-on-rails model-associations
我有4个型号,A,B,C和D.
class A < ActiveRecord::Base
has_many :B
has_many :C, :through => :B
end
class B < ActiveRecord::Base
belongs_to :A
has_many :C
has_many :D, :through => :C
end
class C < ActiveRecord::Base
belongs_to :B
end
class D < ActiveRecord::Base
belongs_to :C
end
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我有一个非常天真的实现,非常明显......
<% A.B.each do |b| %>
<%= b.number %>
<% b.C.each do |c| %>
<%= c.name %>
<% end %>
<% end %>
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获得All C for A的最佳方法是什么?获得All D for A的最佳方式是什么?
我希望使用带有"created_at"值的order_by子句而不是迭代B来获取所有'C'.
可能是我错过了一些ActiveRecord魔法?
我感谢任何帮助.
首先,您需要进行一些更改.
class C 需要一个关联 D
class C < ActiveRecord::Base
belongs_to :B
has_one :D
end
Run Code Online (Sandbox Code Playgroud)如果你想访问A's D',你也需要指定它.
class A < ActiveRecord::Base
has_many :B
has_many :C, :through => :B
has_many :D, :through => :C
end
Run Code Online (Sandbox Code Playgroud)现在,访问所有A的C的:
-> a = A.where(:id => 1).includes(:C).first
A Load (0.2ms) SELECT "as".* FROM "as" WHERE "as"."id" = 1 LIMIT 1
B Load (0.1ms) SELECT "bs".* FROM "bs" WHERE "bs"."a_id" IN (1)
C Load (0.1ms) SELECT "cs".* FROM "cs" WHERE "cs"."b_id" IN (1, 2)
=> #<A id: 1, created_at: "2012-01-10 04:28:42", updated_at: "2012-01-10 04:28:42">
-> a.C
=> [#<C id: 1, b_id: 1, created_at: "2012-01-10 04:30:10", updated_at: "2012-01-10 04:30:10">, #<C id: 2, b_id: 1, created_at: "2012-01-10 04:30:11", updated_at: "2012-01-10 04:30:11">, #<C id: 3, b_id: 2, created_at: "2012-01-10 04:30:21", updated_at: "2012-01-10 04:30:21">, #<C id: 4, b_id: 2, created_at: "2012-01-10 04:30:21", updated_at: "2012-01-10 04:30:21">]
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请注意调用时如何不执行另一个查询a.C.这是因为ActiveRecord知道您将要通过调用访问找到A的,并生成最少数量的查询.同样适用于:CincludeD
-> a = A.where(:id => 1).includes(:D).first
A Load (0.1ms) SELECT "as".* FROM "as" WHERE "as"."id" = 1 LIMIT 1
B Load (0.1ms) SELECT "bs".* FROM "bs" WHERE "bs"."a_id" IN (1)
C Load (0.1ms) SELECT "cs".* FROM "cs" WHERE "cs"."b_id" IN (1, 2)
D Load (0.1ms) SELECT "ds".* FROM "ds" WHERE "ds"."c_id" IN (1, 2, 3, 4)
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假设你希望所有A的D的,但希望C的命令:
A.where(:id => 1).includes(:C).order('cs.created_at DESC').includes(:D)
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请注意,您还可以将此设置为关联的默认值:
该
:order选项指示将接收关联对象的顺序(在SQLORDER BY子句使用的语法中).Run Code Online (Sandbox Code Playgroud)class Customer < ActiveRecord::Base has_many :orders, :order => "date_confirmed DESC" end