当我用来openStream()从Web服务解析XML时,我收到错误:
无法打开流
我检查了URL,它仍然有效.
URL url = new URL("http://uitbookshop.php0h.com/PHPService/findbyname.php?name=thu");
Log.d("search", "getXML::url "+url.toString());
InputStream iS;
try {
iS = url.openStream();
doc=db.parse(new InputSource(new InputStreamReader(iS, Charset.forName("utf-8"))));
} catch (IOException e) {
Log.e("search", "Can not open stream");
} catch (SAXException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}