COUNT（*）GROUP BY

Question

我有一个查询，该查询返回644行，按几列分组。我需要对这些行进行计数644。

这是查询：

SELECT DISTINCT ho.ID,ho.honame,ho.ho_status,SUM(Properties.Value) as [sales value], COUNT(Properties.record_id) as [property count]
FROM HeadOffice ho INNER JOIN Properties ON Properties.head_office_code = ho.id
WHERE Somecondition
GROUP BY ho.ID,ho.honame,ho_status ORDER BY ho_status

尽管尝试过COUNT(*)，将其包装在另一个查询中并删除了GROUP BY，但我无法返回“ 644”。我最接近的是644行，所有行都包含“ 1”。这可能吗？

Answer 1

因此，简单的方法是：

SELECT count(1) as NumRows from
(SELECT DISTINCT ho.ID,ho.honame,ho.ho_status,SUM(Properties.Value) as [sales value], COUNT(Properties.record_id) as [property count]
FROM HeadOffice ho INNER JOIN Properties ON clients.head_office_code = ho.id
WHERE Somecondition
GROUP BY ho.ID,ho.honame,ho_status ORDER BY ho_status) x

如果需要计数加列，请使用over：

SELECT 
    count(1) over () as NumRows,
    x.ID,
    x.ho_status,
    x.[sales value],
    x.[property count]
from
(SELECT DISTINCT ho.ID,ho.honame,ho.ho_status,SUM(Properties.Value) as [sales value], COUNT(Properties.record_id) as [property count]
FROM HeadOffice ho INNER JOIN Properties ON clients.head_office_code = ho.id
WHERE Somecondition
GROUP BY ho.ID,ho.honame,ho_status ORDER BY ho_status) x