ris*_*shi 3 iphone cocoa objective-c
有3个修饰符:@ private,@ protected(默认)和@public.因此,如果我将实例变量定义为私有,那么不应该从任何地方访问它.对于Eg -
@interface A {
@private
NSString *a;
}
@property(nonatomic, retain) NSString *a;
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现在内部实现一些其他接口/类B-
-(void)getSomeValue {
A *object = [[A alloc] init];
NSString *value = object.a;
.........
}
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在这里,我能够访问实例变量,虽然我将其定义为私有.
这有点令人困惑,虽然当我查看这个语句的细节时,很明显它正在调用a的getter,但是它也似乎令人困惑,它违背了OOPS的概念.
有没有想过这个?
tob*_*yer 10
它不是您正在访问的实例变量,而是您声明的属性.如果您不希望实例变量在类外部可见,请不要声明该属性.
#import <Foundation/Foundation.h>
@interface Visibility : NSObject {
@public
BOOL boolPublic;
@protected
BOOL boolProtected;
@private
BOOL boolPrivate;
}
@property (nonatomic, assign) BOOL boolPublic;
@property (nonatomic, assign) BOOL boolProtected;
@property (nonatomic, assign) BOOL boolPrivate;
@end
@implementation Visibility
@synthesize boolPublic;
@synthesize boolProtected;
@synthesize boolPrivate;
@end
int main(int argc, char *argv[]) {
NSAutoreleasePool *pool = [[NSAutoreleasePool alloc] init];
Visibility *visibility = [[Visibility alloc] init];
visibility.boolPublic = YES;
visibility.boolProtected = YES;
visibility.boolPrivate = YES;
// Place following NSLog()'s here
[pool release];
}
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我们来试试吧
使用@ property/@ synthesize定义的方法
NSLog(@"Accessors %d %d %d", visibility.boolPublic, visibility.boolProtected, visibility.boolPrivate);
=> 2012-01-08 17:46:40.226 Untitled[2592:707] Accessors 1 1 1
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直接访问@public ivar
NSLog(@"Public %d", visibility->boolPublic);
=> 2012-01-08 17:46:40.228 Untitled[2592:707] Public 1
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直接访问@protected ivar
NSLog(@"Protected %d", visibility->boolProtected);
=> error: instance variable 'boolProtected' is protected
=> NSLog(@"Protected %d", visibility->boolProtected);
=> ^
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直接访问@private ivar
NSLog(@"Private %d", visibility->boolPrivate);
=> error: instance variable 'boolPrivate' is private
=> NSLog(@"Private %d", visibility->boolPrivate);
=> ^
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当您使用点表示法访问时:
visibility.boolPublic
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相当于:
[visibility boolPublic]; // <- This is a method call
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