如何在Android中以XML格式发送SOAP请求和解析SOAP响应？

Question

对Android应用程序开发来说是一个新手.在我的新Android应用程序中,我想显示来自webservice的一些数据.这意味着我有一个SOAP message,我需要解析SOAP响应中的数据.在iPhone应用程序中,我非常清楚解析SOAP消息响应,但在android中我不知道如何做到这一点？我在谷歌搜索了很多并获得了一些想法.但是,我对此非常困惑.任何人都可以请建议,了解SOAP请求发送/接收响应,并解析(任何最简单的方法XML format)在响应SAXParser中Android？我安装ksoap2-android-assembly-2.6.0-jar-with-dependencies.jar在我的项目中.在这里我找到了一些示例代码,我在这里发布,

import java.io.*;
import org.ksoap2.SoapEnvelope;
import org.kxml2.io.KXmlParser;
import org.xmlpull.v1.XmlPullParserException;


public class ParsingSteps 
{
  public static void main(String[] args) 
   {
     try{
       // String msg="<hello>World!</hello>";
        String msg = "<SOAP-ENV:Envelope " + "xmlns:SOAP-ENV=\"http://
www.w3.org/2001/12/soap-envelope\" " + "xmlns:xsi=\"http://www.w3.org/
 2001/XMLSchema-instance <http://www.w3.org/%0A2001/XMLSchema-instance>\""
 +"xmlns:xsd=\"http://www.w3.org/2001/
 XMLSchema\"& gt;" +
         "<SOAP-ENV:Body>" +
         "<result>" +
         "<message xsi:type=\"xsd:string\">Hello World</message>" +
        "</result>" +
        "</SOAP-ENV:Body>" +
        "</SOAP-ENV:Envelope>";

      //  byte[] in= msg.getBytes();

        KXmlParser parser=new KXmlParser();
       parser.setInput(new StringReader(msg));
       SoapEnvelope soapenvelope= new SoapEnvelope
(SoapEnvelope.VER12);
        //soapenvelope.parse(parser);
        soapenvelope.parseBody(parser);

          }
       catch (IOException e) {
               System.out.println("Error reading URI: " + e.getMessage ());
       } catch (XmlPullParserException e) {
              System.out.println("Error in parsing: " + e.getMessage ());
       }
      //  String result=parser.getName();
       //System.out.println(result);
    }
 }

这是正确的代码吗？请对我的问题提出任何建议.请帮帮我.提前致谢.

Answer 1

Google for Ksoap2教程你会得到很多.以下是向Web服务发送请求的示例代码.

public class WebServicePoc extends Activity{
private static final String SOAP_ACTION = "http://tempuri.org/Arnoid";
private static final String METHOD_NAME = "Arnoid";
private static final String NAMESPACE = "http://tempuri.org/";
private static final String URL = "http://ipaddress:port/UserAuthenticationInterfacer.asmx";
EditText editText;
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);
    HashMap<String, String> a=new HashMap<String, String>();
    try {

        SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
        request.addProperty("FOSID", "1994");
        request.addProperty("IMEINumber", "");
        request.addProperty("SIMCardNo", "");
        request.addProperty("ApplicationName", "App");
        request.addProperty("CurrentVersion", "1.0.0.0");
        SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
        envelope.dotNet=true;
        envelope.setOutputSoapObject(request);
        AndroidHttpTransport androidHttpTransport = new AndroidHttpTransport(URL);
        androidHttpTransport.call(SOAP_ACTION, envelope);
        SoapObject result = (SoapObject)envelope.getResponse();
        editText=(EditText)findViewById(R.id.text1);
        editText.setText(result.toString());
    } catch (Exception e) {
        e.printStackTrace();
    }

对于xml pls,请查看xml解析器的教程,仅使用SAX,因为android中不支持STAX.对于发送xml请求,你可以将xml作为字符串发送,然后在服务器端解码.