Alv*_*gui 2 javascript greasemonkey xmlhttprequest userscripts http-headers
我一直在寻找一段时间,但我能找到的只是如何实际提出这些要求的例子......
我要做的是在点击X站点的按钮后检查网站是否正在发出http请求
防爆.http://test.s3.amazonaws.com/test/1.txt
我猜有一种方法来获取所有传出的请求,然后过滤列表,但我甚至无法得到请求
到目前为止我所做的只是插入eventlistener以检查是否已单击X按钮,然后是我想要检查这些请求的时间.
<script language="javascript">
document.getElementById("button").addEventListener('click', buttonClicked, true);
function buttonClicked(){
-->Check requests made after button is clicked.<--
}
</script>
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我刚才做了一个基本的脚本,基本上你只是包装了内置的XMLHttpRequest.
(function() {
'use strict';
var oldXHR, stateChangeHandler, prop;
oldXHR = window.XMLHttpRequest;
stateChangeHandler = function (evt) {
switch (this.readyState) {
case oldXHR.OPENED:
console.log('Request was made', this, evt);
break;
case oldXHR.DONE:
console.log('Request finished', this, evt);
break;
}
};
function newXHR() {
var xhr = new oldXHR();
xhr.addEventListener('readystatechange', stateChangeHandler);
return xhr;
}
// Copy original states and toString
for (prop in oldXHR)
newXHR[prop] = oldXHR[prop];
window.XMLHttpRequest = newXHR;
})();
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