阅读plist文件

Question

我在其中创建了带有大量不同动物的plist(键),并在我的项目中添加了这个plist.每种动物的类型都是NSDictionary.在每个字典中还有5个键 - 这些动物的特征().我想通过每一种动物,如果我匹配这种动物的某些特征,我把这种动物放在另一个阵列中.

所以,我试着制作一个代码:

NSArray *newArray = [[NSArray alloc]initWithContentsOfFile:[[NSBundle mainBundle] pathForResource:@"animals" ofType:@"plist"]];    

for (int i = 0;[newArray objectAtIndex:i];i++)    
{      
      if ([[newArray objectAtIndex:i]objectForKey:@"minAge"] == [NSNumber numberWithInt:3]) 
      {            
              [array addObject:[[newArray objectAtIndex:i]objectForKey:@"name"]];                  
      }
}

所以objectAtIndex:i是一个动物,minAge是它的特点之一.但我的代码不起作用.我是第一次这样做,所以我做错了什么？谢谢!

更新:谢谢,你的plist工作正常!但我仍然无法理解为什么我的plist不起作用:

无论如何,非常感谢你!我在解决这个问题的时候没有吃饭和睡觉:)你帮助了我很多!

Answer 1

NSArray 如果无法打开文件或无法将文件内容解析为数组,则返回值为nil.

我怀疑问题是您需要将内容放在NSDictionary而不是NSArray中

 NSDictionary *theDict = [NSDictionary dictionaryWithContentsOfFile:plistFile];

编辑.进一步回答我的问题

NSMutableArray *mutableArray =[[NSMutableArray alloc] initWithObjects:nil];
NSDictionary *mainDictionary = [NSDictionary dictionaryWithContentsOfFile:[[NSBundle mainBundle] pathForResource:@"animals" ofType:@"plist"]];

   //--get parent dictionary/Array named animals which holds the animals dictionary items
    NSDictionary *parentDictionary = [mainDictionary objectForKey:@"animals"];


    //---enumerate through the dictionary objects inside the parentDictionary
    NSEnumerator *enumerator = [parentDictionary objectEnumerator];
    id value;

    while ((value = [enumerator nextObject])) {
        if ([[value valueForKey:@"minAge"] isEqualToNumber:[NSNumber numberWithInt:3]]) 
        {            

            [mutableArray addObject:[value valueForKey:@"name"]];                  
        }


    }

如果动物词典不在父词典或数组中,请使用类似的内容

NSMutableArray *mutableArray =[[NSMutableArray alloc] initWithObjects:nil];

    NSDictionary *mainDictionary = [NSDictionary dictionaryWithContentsOfFile:[[NSBundle mainBundle] pathForResource:@"animals" ofType:@"plist"]];




    //---enumerate through the dictionary objects 
    NSEnumerator *enumerator = [mainDictionary objectEnumerator];
    id value;

    while ((value = [enumerator nextObject])) {
        if ([[value valueForKey:@"minAge"] isEqualToNumber:[NSNumber numberWithInt:3]]) 
        {            

            [mutableArray addObject:[value valueForKey:@"name"]];                  
        }


    }

编辑.1.

试试这个plist吧.确保使用纯文本编辑器将其粘贴到并保存为plist文件

编辑.2.我现在更新了我的plist以匹配你的.虽然另一个工作.我觉得我们使用同样的东西会更有意义.

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE plist PUBLIC "-//Apple//DTD PLIST 1.0//EN" "http://www.apple.com/DTDs/PropertyList-1.0.dtd">
<plist version="1.0">
<dict>
    <key>Whale</key>
    <dict>
        <key>name</key>
        <string>Whale</string>
        <key>isMale</key>
        <true/>
        <key>color</key>
        <string>blue</string>
        <key>maxAge</key>
        <integer>8</integer>
        <key>minAge</key>
        <integer>3</integer>
    </dict>
    <key>Dolphin</key>
    <dict>
        <key>maxAge</key>
        <integer>20</integer>
        <key>name</key>
        <string>Dolphin</string>
        <key>isMale</key>
        <false/>
        <key>color</key>
        <string>blue</string>
        <key>minAge</key>
        <integer>15</integer>
    </dict>
</dict>
</plist>

另外,这是另一个示例,显示如何将布尔值和数字进行比较

NSMutableArray *theAnimalMatched =[[NSMutableArray alloc] initWithObjects:nil];


    NSDictionary *mainDictionary = [NSDictionary dictionaryWithContentsOfFile:[[NSBundle mainBundle] pathForResource:@"data1" ofType:@"plist"]];



    //---enumerate through the dictionary objects inside the rootDictionary
    NSEnumerator *enumerator = [mainDictionary objectEnumerator];
    id returnValue;

 while ((returnValue = [enumerator nextObject])) {

         if ( [[returnValue valueForKey:@"isMale" ] boolValue] && [[returnValue valueForKey:@"minAge"] isEqualToNumber:[NSNumber numberWithInt:3]] && [[returnValue valueForKey:@"color"] isEqualToString:@"blue"]  )  
         {  

        [theAnimalMatched addObject:[returnValue valueForKey:@"name"]];                  
    }


}