BI *_*ude 5 sql t-sql sql-server
我真的需要一个简单求和的表上的计算列.
请看下面:
SELECT key3
,SUM(UTOTALWBUD)
FROM CONTACT1
INNER JOIN CONTACT2
ON CONTACT1.ACCOUNTNO = CONTACT2.ACCOUNTNO
WHERE KEY1 = 'Client'
GROUP BY KEY3
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我试图通过添加以下内容来创建计算列
ALTER TABLE ManagerTaLog
ADD WeeklyBudget as ( SELECT
key3
,SUM(UTOTALWBUD)
FROM CONTACT1
JOIN CONTACT2
ON CONTACT1.ACCOUNTNO = CONTACT2.ACCOUNTNO
WHERE KEY1 = 'Client'
GROUP BY KEY3)
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我收到了错误消息:
在此上下文中不允许Msg 1046,级别15,状态1,行4 子查询.只允许标量表达式.
请告知我该怎么办.
非常感谢
我创造了一个功能; 但是,我得到空值,请指教.
CREATE FUNCTION [dbo].[SumIt](@Key3 varchar)
RETURNS TABLE
AS
RETURN
(
SELECT SUM(UTOTALWBUD)
FROM CONTACT1
JOIN CONTACT2
ON CONTACT1.ACCOUNTNO = CONTACT2.ACCOUNTNO
JOIN Phone_List
ON CONTACT1.KEY3 = Phone_List.[Manager ]
WHERE KEY1 = 'Client'
AND Phone_List.[Manager ] = @Key3
GROUP BY [Manager ]
)
END
GO
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只需选择返回我想要添加到Phone_list表的值的语句
SELECT [Manager ]
,SUM(UTOTALWBUD)
FROM CONTACT1
JOIN CONTACT2
ON CONTACT1.ACCOUNTNO = CONTACT2.ACCOUNTNO
JOIN Phone_List
ON CONTACT1.KEY3 = Phone_List.[Manager ]
WHERE KEY1 = 'Client'
GROUP BY [Manager ]
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CREATE TABLE [dbo].[CONTACT1](
[ACCOUNTNO] [varchar](20) NOT NULL,
[COMPANY] [varchar](40) NULL,
[CONTACT] [varchar](40) NULL,
[LASTNAME] [varchar](15) NULL,
[DEPARTMENT] [varchar](35) NULL,
[TITLE] [varchar](35) NULL,
[SECR] [varchar](20) NULL,
[PHONE1] [varchar](25) NOT NULL,
[PHONE2] [varchar](25) NULL,
[PHONE3] [varchar](25) NULL,
[FAX] [varchar](25) NULL,
[EXT1] [varchar](6) NULL,
[EXT2] [varchar](6) NULL,
[EXT3] [varchar](6) NULL,
[EXT4] [varchar](6) NULL,
[ADDRESS1] [varchar](40) NULL,
[ADDRESS2] [varchar](40) NULL,
[ADDRESS3] [varchar](40) NULL,
[CITY] [varchar](30) NULL,
[STATE] [varchar](20) NULL,
[ZIP] [varchar](10) NOT NULL,
[COUNTRY] [varchar](20) NULL,
[DEAR] [varchar](20) NULL,
[SOURCE] [varchar](20) NULL,
[KEY1] [varchar](20) NULL,
[KEY2] [varchar](20) NULL,
[KEY3] [varchar](20) NULL,
[KEY4] [varchar](20) NULL,
[KEY5] [varchar](20) NULL,
[STATUS] [varchar](3) NOT NULL,
[NOTES] [text] NULL,
[MERGECODES] [varchar](20) NULL,
[CREATEBY] [varchar](8) NULL,
[CREATEON] [datetime] NULL,
[CREATEAT] [varchar](5) NULL,
[OWNER] [varchar](8) NOT NULL,
[LASTUSER] [varchar](8) NULL,
[LASTDATE] [datetime] NULL,
[LASTTIME] [varchar](5) NULL,
[U_COMPANY] [varchar](40) NOT NULL,
[U_CONTACT] [varchar](40) NOT NULL,
[U_LASTNAME] [varchar](15) NOT NULL,
[U_CITY] [varchar](30) NOT NULL,
[U_STATE] [varchar](20) NOT NULL,
[U_COUNTRY] [varchar](20) NOT NULL,
[U_KEY1] [varchar](20) NOT NULL,
[U_KEY2] [varchar](20) NOT NULL,
[U_KEY3] [varchar](20) NOT NULL,
[U_KEY4] [varchar](20) NOT NULL,
[U_KEY5] [varchar](20) NOT NULL,
[recid] [varchar](15) NOT NULL
) ON [PRIMARY] TEXTIMAGE_ON [PRIMARY]
GO
CREATE TABLE [dbo].[Phone_List](
[Manager ] [nvarchar](255) NULL,
[SalesCode] [nvarchar](255) NULL,
[Email] [nvarchar](255) NULL,
[PayrollCode] [nvarchar](255) NULL,
[Mobile] [nvarchar](255) NULL,
[FName] [nchar](20) NULL,
[idd] [tinyint] NULL,
[OD] [varchar](20) NULL,
[WeeklyBudget] AS ([dbo].[SumIt]([manager]))
) ON [PRIMARY]
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你可以用你的查询到这样的(它的功能HAS返回一个值):
CREATE FUNCTION dbo.SumIt(@Key1 varchar(max))
returns float
as
begin
return (select sum(UTOTALWBUD) from
CONTACT1 inner join
CONTACT2 on
CONTACT1.ACCOUNTNO=CONTACT2.ACCOUNTNO
where KEY1=@key1
group by KEY3)
END
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并使用此函数代替calc字段 - 如下所示:
alter table ManagerTaLog add WeeklyBudget as dbo.SumIt(Key1)
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注意
它将成为这样的查询的性能杀手:
select * from ManagerTaLog
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您应该以这样的方式更改您的函数,即接受NOT varchar值,但是NVARCHAR(255)- 与Manager列相同的类型.试试吧.
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