C#的常见操作成本？

Question

在代码完成2(第601和602页)中,有一个"常用操作成本"表.

基线操作整数赋值的值为1,然后列出了Java和C++的常用操作的相对时间.例如:

                                  C++        Java
Integer assignment                1             1
Integer division                  5             1.5
Floating point square root       15             4 

问题是有没有人得到C#的这些数据？我知道这些不会帮我解决任何问题,我只是好奇.

Answer 1

我从书中实现了一些测试.我电脑的一些原始数据:

测试运行#1:

TestIntegerAssignment 00:00:00.6680000
TestCallRoutineWithNoParameters 00:00:00.9780000
TestCallRoutineWithOneParameter 00:00:00.6580000
TestCallRoutineWithTwoParameters 00:00:00.9650000
TestIntegerAddition 00:00:00.6410000
TestIntegerSubtraction 00:00:00.9630000
TestIntegerMultiplication 00:00:00.6490000
TestIntegerDivision 00:00:00.9720000
TestFloatingPointDivision 00 :00:00.6500000
TestFloatingPointSquareRoot 00:00:00.9790000
TestFloatingPointSine 00:00:00.6410000
TestFloatingPointLogarithm 00:00:41.1410000
TestFloatingPointExp 00:00:34.6310000

试运行#2:

TestIntegerAssignment 00:00:00.6750000
TestCallRoutineWithNoParameters 00:00:00.9720000
TestCallRoutineWithOneParameter 00:00:00.6490000
TestCallRoutineWithTwoParameters 00:00:00.9750000
TestIntegerAddition 00:00:00.6730000
TestIntegerSubtraction 00:00:01.0300000
TestIntegerMultiplication 00:00:00.7000000
TestIntegerDivision 00:00:01.1120000
TestFloatingPointDivision 00 :00:00.6630000
TestFloatingPointSquareRoot 00:00:00.9860000
TestFloatingPointSine 00:00:00.6530000
TestFloatingPointLogarithm 00:00:39.1150000
TestFloatingPointExp 00:00:33.8730000

试运行#3:

TestIntegerAssignment 00:00:00.6590000
TestCallRoutineWithNoParameters 00:00:00.9700000
TestCallRoutineWithOneParameter 00:00:00.6680000
TestCallRoutineWithTwoParameters 00:00:00.9900000
TestIntegerAddition 00:00:00.6720000
TestIntegerSubtraction 00:00:00.9770000
TestIntegerMultiplication 00:00:00.6580000
TestIntegerDivision 00:00:00.9930000
TestFloatingPointDivision 00 :00:00.6740000
TestFloatingPointSquareRoot 00:00:01.0120000
TestFloatingPointSine 00:00:00.6700000
TestFloatingPointLogarithm 00:00:39.1020000
TestFloatingPointExp 00:00:35.3560000

(每个基准测试10亿次测试,使用Optimize编译,AMD Athlon X2 3.0ghz,使用Jon Skeet的微基准测试框架,网址为http://www.yoda.arachsys.com/csharp/benchmark.html)

资源:

class TestBenchmark  
{  
[Benchmark]  
public static void TestIntegerAssignment()
{
int i = 1;
int j = 2;

    for (int x = 0; x < 1000000000; x++)
    {
        i = j;
    }
}

[Benchmark]
public static void TestCallRoutineWithNoParameters()
{
    for (int x = 0; x < 1000000000; x++)
    {
        TestStaticRoutine();
    }
}

[Benchmark]
public static void TestCallRoutineWithOneParameter()
{
    for (int x = 0; x < 1000000000; x++)
    {
        TestStaticRoutine2(5);
    }
}

[Benchmark]
public static void TestCallRoutineWithTwoParameters()
{
    for (int x = 0; x < 1000000000; x++)
    {
        TestStaticRoutine3(5,7);
    }
}

[Benchmark]
public static void TestIntegerAddition()
{
    int i = 1;
    int j = 2;
    int k = 3;

    for (int x = 0; x < 1000000000; x++)
    {
        i = j + k;
    }
}

[Benchmark]
public static void TestIntegerSubtraction()
{
    int i = 1;
    int j = 6;
    int k = 3;

    for (int x = 0; x < 1000000000; x++)
    {
        i = j - k;
    }
}

[Benchmark]
public static void TestIntegerMultiplication()
{
    int i = 1;
    int j = 2;
    int k = 3;

    for (int x = 0; x < 1000000000; x++)
    {
        i = j * k;
    }
}


[Benchmark]
public static void TestIntegerDivision()
{
    int i = 1;
    int j = 6;
    int k = 3;

    for (int x = 0; x < 1000000000; x++)
    {
        i = j/k;
    }
}

[Benchmark]
public static void TestFloatingPointDivision()
{
    float i = 1;
    float j = 6;
    float k = 3;

    for (int x = 0; x < 1000000000; x++)
    {
        i = j / k;
    }
}

[Benchmark]
public static void TestFloatingPointSquareRoot()
{
    double x = 1;
    float y = 6;

    for (int x2 = 0; x2 < 1000000000; x2++)
    {
        x = Math.Sqrt(6);
    }
}

[Benchmark]
public static void TestFloatingPointSine()
{
    double x = 1;
    float y = 6;

    for (int x2 = 0; x2 < 1000000000; x2++)
    {
        x = Math.Sin(y);
    }
}

[Benchmark]
public static void TestFloatingPointLogarithm()
{
    double x = 1;
    float y = 6;

    for (int x2 = 0; x2 < 1000000000; x2++)
    {
        x = Math.Log(y);
    }
}

[Benchmark]
public static void TestFloatingPointExp()
{
    double x = 1;
    float y = 6;

    for (int x2 = 0; x2 < 1000000000; x2++)
    {
        x = Math.Exp(6);
    }
}

private static void TestStaticRoutine() {

}

private static void TestStaticRoutine2(int i)
{

}

private static void TestStaticRoutine3(int i, int j)
{

}

private static class TestStaticClass
{

}

Answer 2

直接从源头开始，知道东西的成本。

IIRC Rico Mariani 有与您在他的博客上要求的相对措施，但我再也找不到它了（我知道它在两个“开发”书签之一中......）