是否可以将div设置为梯形?

Dou*_*oug 12 css css3 css-transforms css-shapes

我知道有可能歪斜,但我没有办法在特定程度上扭曲每个角落.

这是我正在进行的项目:http://map.ucf.edu/

专门查看菜单中的选项卡.现在我正在使用图像,我想为有能力的浏览器改变它.

我知道可以创建一个CSS trapazoid,但这是使用没有内容的边框.最终结果还需要一些圆角.

编辑:从Zoltan Toth的解决方案开始,我能够实现这一目标:演示

div {
    height: 20px;
    padding:2px 5px 0 5px;
    color:white;
    background: rgba(0,0,0,.5);
    margin: 0 10px;
    position: relative;
    border-top-left-radius: 6px 4px;
    border-top-right-radius: 6px 4px;
    font-family:sans-serif;
    font-size:13px;
    line-height:20px;
    vertical-align:bottom;
    display:inline-block;
    white-space:nowrap;
}

div:before {
    content: '';
    line-height: 0;
    font-size: 0;
    width: 0;
    height: 0;
    border-bottom: 19px solid rgba(0,0,0,.5);
    border-left: 9px solid transparent;
    position: absolute;
    bottom: 0;
    left: -9px;
}

div:after {
    content: '';
    line-height: 0;
    font-size: 0;
    width: 0;
    height: 0;
    border-bottom: 19px solid rgba(0,0,0,.5);
    border-right: 9px solid transparent;
    position: absolute;
    bottom: 0;
    right: -9px;
}

.b { background:black; margin:0 -7px 0 20px; }
.b:after, .b:before { border-bottom-color:black; }
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Zol*_*oth 14

这是可能的,这是一个粗略的想法:

div {
    width: 200px;
    height: 100px;
    background: #ddd;
    margin: 20px 150px;
    position: relative
}

div:before {
    content: '';
    line-height: 0;
    font-size: 0;
    width: 0;
    height: 0;
    border-top: 50px solid transparent;
    border-bottom: 50px solid #ddd;
    border-left: 50px solid transparent;
    border-right: 50px solid #ddd;
    position: absolute;
    top: 0;
    left: -99px;
}

div:after {
    content: '';
    line-height: 0;
    font-size: 0;
    width: 0;
    height: 0;
    border-top: 50px solid transparent;
    border-bottom: 50px solid #ddd;
    border-left: 50px solid #ddd;
    border-right: 50px solid transparent;
    position: absolute;
    top: 0;
    right: -99px;
}
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<div>Hello</div>

<div>Lorem ipsum dolor sit amet, consectetur adipiscing elit. Etiam cursus ex quis enim posuere auctor.</div>
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