numpy中的数组索引

Question

numpy中是否有一种方法可以检索数组中除提供的索引项之外的所有项.

 x = 
 array([[[4, 2, 3],
    [2, 0, 1],
    [1, 3, 4]],

   [[2, 1, 2],
    [3, 2, 3],
    [3, 4, 2]],

   [[2, 4, 1],
    [0, 2, 2],
    [4, 0, 0]]])

并要求

x[not 1,:,:] 

你会得到

array([[[4, 2, 3],
    [2, 0, 1],
    [1, 3, 4]],

   [[2, 4, 1],
    [0, 2, 2],
    [4, 0, 0]]])

谢谢

Answer 1

In [42]: x[np.arange(x.shape[0])!=1,:,:]
Out[42]: 
array([[[4, 2, 3],
        [2, 0, 1],
        [1, 3, 4]],

       [[2, 4, 1],
        [0, 2, 2],
        [4, 0, 0]]])