itc*_*y23 4 list record sml smlnj
我正在尝试声明一个函数,它将元组中的记录列表作为参数,但语法并不像我希望的那样直观.
这是我正在尝试做的事情:
type Player = {id:int, privateStack:int list};
fun foo(({id, x::xs}:Player)::players, ...) = (* wrong syntax *)
(* do something *)
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模式匹配需要将记录字段绑定到某些值,因此您必须使用显式记录语法.因此,
fun foo(({id = id, privateStack = x::xs})::players, ...) =
(* do something *)
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会工作.
请注意,上面的模式匹配并不详尽,请注意空列表players和空列表privateStack:
fun foo([], ...) = (* do something *)
| foo({id = id, privateStack = []}::players, ...) = (* do something else *)
| foo({id = id, privateStack = x::xs}::players, ...) = (* do something else *)
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