use*_*523 2 java regex validation
我有一个文本框,它接受格式为HH:mm的时间,条目应该只有24小时格式.对于所有无效条目,应显示常见消息"无效条目".
例如:
19:61 //INVALID
12:00am //INVALID
12***M //INVALID
06:00 //VALID
22:00 //VALID
5:45 //VALID
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所需的代码是Java.不熟悉正则表达式...所以需要你的想法.Thx提前!:)
String timeStr = getTimeBoxValue();
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有一个链接 ,您可以使用.
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Time24HoursValidator{
private Pattern pattern;
private Matcher matcher;
private static final String TIME24HOURS_PATTERN =
"([01]?[0-9]|2[0-3]):[0-5][0-9]";
public Time24HoursValidator(){
pattern = Pattern.compile(TIME24HOURS_PATTERN);
}
/**
* Validate time in 24 hours format with regular expression
* @param time time address for validation
* @return true valid time fromat, false invalid time format
*/
public boolean validate(final String time){
matcher = pattern.matcher(time);
return matcher.matches();
}
}
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