如何在python中删除路径前缀？

Question

我想知道什么是pythonic函数:

我想删除wa路径前的所有内容.

p = path.split('/')
counter = 0
while True:
    if p[counter] == 'wa':
        break
    counter += 1
path = '/'+'/'.join(p[counter:])

例如,我想'/book/html/wa/foo/bar/'成为'/wa/foo/bar/'.

Answer 1

更好的答案是使用os.path.relpath:

http://docs.python.org/2/library/os.path.html#os.path.relpath

>>> import os
>>> full_path = '/book/html/wa/foo/bar/'
>>> print os.path.relpath(full_path, '/book/html')
'wa/foo/bar'

Answer 2

>>> path = '/book/html/wa/foo/bar/'
>>> path[path.find('/wa'):]
'/wa/foo/bar/'

Answer 3

对于Python 3.4+,您应该使用pathlib.PurePath.relative_to.从文档:

>>> p = PurePosixPath('/etc/passwd')
>>> p.relative_to('/')
PurePosixPath('etc/passwd')

>>> p.relative_to('/etc')
PurePosixPath('passwd')

>>> p.relative_to('/usr')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "pathlib.py", line 694, in relative_to
    .format(str(self), str(formatted)))
ValueError: '/etc/passwd' does not start with '/usr'

另请参阅此StackOverflow问题以获取更多问题的答案.