PHP搜索JSON的价值

Question

所以我有一个json对象,其结构如下:

{
"John Doe": [
    {
        "childName": "Harry",
        "childAge": 15,
        "childGender": "Male"
    },
    {
        "childName": "Sally",
        "childAge": 9,
        "childGender": "Female"
    },
],
"Miss Piggy": [
    {
        "childName": "Jane",
        "childAge": 20,
        "childGender": "Female"
    }
],

}

我想要做的是能够查询childName,childAge或childGender,并返回该子对象(如果已找到).

例如:

searchJson($jsonObj, 'childName', 'Sally') // returns {"childName":"Sally", "childAge":9,"childGender":"Female"}

在这方面最好的方法是什么？

Answer 1

function searchJson($obj, $field, $value) {
    foreach($obj as $item) {
        foreach($item as $child) {
            if(isset($child->$field) && $child->$field == $value) {
                return $child;
            }
        }
    }
    return null;
}