XSLT中的身份转换

Question

我有这个源XML:

<?xml version="1.0"?>
<root>
   <item1>
      <name>test</name>
      <price>160</price>
      <stock>4</stock>
      <country>Belgium</country>
   </item1>
   <item2>
      <name>Alfa</name>

      <price>140</price>

      <stock>3</stock>

      <country>Turkey</country>
   </item2>
   <item3>
      <name>Beta</name>

      <price>110</price>

      <stock>48</stock>

      <country>Holland</country>
   </item3>
   <product id="p1">
      <name>Delta</name>

      <price>800</price>

      <stock>4</stock>

      <country>Denmark</country>
   </product>
   <product id="p2">
      <name>Golf</name>

      <price>1000</price>

      <stock>5</stock>

      <country>Germany</country>
   </product>
   <product id="p3">
      <name>Alfa</name>

      <price>1200</price>

      <stock>19</stock>

      <country>Germany</country>
   </product>
   <product id="p4">
      <name>Foxtrot</name>

      <price>1500</price>

      <stock>5</stock>

      <country>Australia</country>
   </product>
   <product id="p5">
      <name>Tango</name>

      <price>1225</price>

      <stock>3</stock>

      <country>Japan</country>
   </product>
</root>

我希望它看起来像这样:

<?xml version="1.0"?>
<root>
   <action>
      <name>test</name>

      <price>160</price>

      <stock>4</stock>

      <country>Belgium</country>
   </action>
   <action>
      <name>Alfa</name>

      <price>140</price>

      <stock>3</stock>

      <country>Turkey</country>
   </action>
   <action>
      <name>Beta</name>

      <price>110</price>

      <stock>48</stock>

      <country>Holland</country>
   </action>
   <action>
      <name>Delta</name>

      <price>800</price>

      <stock>4</stock>

      <country>Denmark</country>
   </action>
   <action>
      <name>Golf</name>

      <price>1000</price>

      <stock>5</stock>

      <country>Germany</country>
   </action>
   <action>
      <name>Alfa</name>

      <price>1200</price>

      <stock>19</stock>

      <country>Germany</country>
   </action>
   <action>
      <name>Foxtrot</name>

      <price>1500</price>

      <stock>5</stock>

      <country>Australia</country>
   </action>
   <action>
      <name>Tango</name>

      <price>1225</price>

      <stock>3</stock>

      <country>Japan</country>
   </action>
</root>

所以<item1>要<item3转变为

<action>

而<product>失去了它的属性,也变成了

<action>

有人可以告诉我如何使用XSLT做到这一点？因为我现在有2种不同的XSL.我想将它们组合起来只创建一个XSL.

提前致谢

Answer 1

这种转变:

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:strip-space elements="*"/>

 <xsl:template match="node()|@*">
     <xsl:copy>
       <xsl:apply-templates select="node()|@*"/>
     </xsl:copy>
 </xsl:template>

 <xsl:template match="product|*[starts-with(name(), 'item')]">
  <action>
   <xsl:apply-templates select="node()|@*"/>
  </action>
 </xsl:template>

 <xsl:template match="product/@id"/>
</xsl:stylesheet>

当应用于提供的XML文档时:

<root>
    <item1>
        <name>test</name>
        <price>160</price>
        <stock>4</stock>
        <country>Belgium</country>
    </item1>
    <item2>
        <name>Alfa</name>
        <price>140</price>
        <stock>3</stock>
        <country>Turkey</country>
    </item2>
    <item3>
        <name>Beta</name>
        <price>110</price>
        <stock>48</stock>
        <country>Holland</country>
    </item3>
    <product id="p1">
        <name>Delta</name>
        <price>800</price>
        <stock>4</stock>
        <country>Denmark</country>
    </product>
    <product id="p2">
        <name>Golf</name>
        <price>1000</price>
        <stock>5</stock>
        <country>Germany</country>
    </product>
    <product id="p3">
        <name>Alfa</name>
        <price>1200</price>
        <stock>19</stock>
        <country>Germany</country>
    </product>
    <product id="p4">
        <name>Foxtrot</name>
        <price>1500</price>
        <stock>5</stock>
        <country>Australia</country>
    </product>
    <product id="p5">
        <name>Tango</name>
        <price>1225</price>
        <stock>3</stock>
        <country>Japan</country>
    </product>
</root>

产生想要的,正确的结果:

<root>
   <action>
      <name>test</name>
      <price>160</price>
      <stock>4</stock>
      <country>Belgium</country>
   </action>
   <action>
      <name>Alfa</name>
      <price>140</price>
      <stock>3</stock>
      <country>Turkey</country>
   </action>
   <action>
      <name>Beta</name>
      <price>110</price>
      <stock>48</stock>
      <country>Holland</country>
   </action>
   <action>
      <name>Delta</name>
      <price>800</price>
      <stock>4</stock>
      <country>Denmark</country>
   </action>
   <action>
      <name>Golf</name>
      <price>1000</price>
      <stock>5</stock>
      <country>Germany</country>
   </action>
   <action>
      <name>Alfa</name>
      <price>1200</price>
      <stock>19</stock>
      <country>Germany</country>
   </action>
   <action>
      <name>Foxtrot</name>
      <price>1500</price>
      <stock>5</stock>
      <country>Australia</country>
   </action>
   <action>
      <name>Tango</name>
      <price>1225</price>
      <stock>3</stock>
      <country>Japan</country>
   </action>
</root>

说明:

1. 身份规则"按原样"复制每个节点.

2. 我们有两个模板覆盖了身份规则.第一个模板匹配product名称以字符串开头的任何或任何元素item.它action通过创建和输出action元素有效地"重命名"匹配的元素.

3. 第二个重写模板匹配id任何product元素的任何属性.此模板没有主体,它有效地"删除"匹配的属性 - 它不会在输出中复制/重新创建.