ark*_*tal 1 c# listview expandablelistview xamarin.android
我试图做这个例子http://techdroid.kbeanie.com/2010/09/expandablelistview-on-android.html,但是使用monodroid,我的问题是我习惯用java编程但是我hava问题给孩子打电话在BaseExpandableListAdapter Abstracs方法上列出,因为我需要例如从列表中放入groupPosition和childPosition,所以我该如何解决这个问题呢?
创建一个问题ExpandableListAdapter的方法是,这些方法要求您返回Java.Lnag.Object.我无法让您的Java示例工作的类型.
但是这里有一个使用a ExpandableListView而不是定义自己ExpandableListAdapter而不仅仅是使用SimpleExpandableListAdapter类的例子.
此示例将使您能够使用ExpandableListView它,但它不会为您提供附加的灵活性BaseExpandableListAdapter.
using System;
using System.Collections.Generic;
using Android.App;
using Android.Content;
using Android.OS;
using Android.Runtime;
using Android.Views;
using Android.Widget;
namespace Scratch.ExpandableListActivity
{
[Activity (Label = "Scratch.ExpandableListActivity", MainLauncher = true)]
public class Activity1 : Android.App.ExpandableListActivity
{
IExpandableListAdapter mAdapter;
const string Name = "NAME";
const string IsEven = "IS_EVEN";
protected override void OnCreate(Bundle bundle)
{
base.OnCreate(bundle);
using (var groupData = new JavaList<IDictionary<string, object>> ())
using (var childData = new JavaList<IList<IDictionary<string, object>>> ()) {
for (int i = 0; i < 20; i++) {
using (var curGroupMap = new JavaDictionary<string, object>()) {
groupData.Add(curGroupMap);
curGroupMap.Add(Name, "Group " + i);
curGroupMap.Add(IsEven, (i % 2 == 0) ? "This group is even" : "This group is odd");
using (var children = new JavaList<IDictionary<string, object>> ()) {
for ( int j = 0; j < 15; j++) {
using (var curChildMap = new JavaDictionary<string, object> ()) {
children.Add(curChildMap);
curChildMap.Add(Name, "Child " + j);
curChildMap.Add(IsEven, (j % 2 == 0) ? "This child is even" : "This child is odd");
}
}
childData.Add(children);
}
}
}
// Set up our adapter
mAdapter = new SimpleExpandableListAdapter (
this,
groupData,
Android.Resource.Layout.SimpleExpandableListItem1,
new string[] { Name, IsEven},
new int[] { Android.Resource.Id.Text1, Android.Resource.Id.Text2 },
childData,
Android.Resource.Layout.SimpleExpandableListItem2,
new string[] { Name, IsEven },
new int[] { Android.Resource.Id.Text1, Android.Resource.Id.Text2 }
);
SetListAdapter(mAdapter);
}
}
}
}
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