MTA*_*MTA 21 html javascript html5
我使用此代码上传文件到服务器(在HTML中):
<form action="" method="post" enctype="multipart/form-data" name="form1" id="form1">
<label>upload file<input type="file" name="file" id="file" /></label>
<label><input type="submit" name="button" id="button" value="Submit" /></label></form>
它是打开文件浏览器,让我选择一个文件,当我按下提交文件时,将文件发送到我的服务器.
我想知道是否有办法让多个文件选择.
js-*_*der 54
您可以使用该multiple属性,如下所示:
<input type="file" multiple />
要选择多个文件,您需要Ctrl按键并单击要添加的文件.
lk.*_*lai 13
使用Spring Framework进行多文件选择和上载
在这篇文章中,我描述了多文件上传的服务器端和客户端代码.
以下代码用于提及appContext.xml中的多部分数据
appContext.xml
<bean id="multipartResolver" class="org.springframework.web.multipart.commons.CommonsMultipartResolver">
<!-- one of the properties available; the maximum file size in bytes -->
<property name="maxUploadSize" value="20971520"/>
</bean>
Simpleupload.jsp:
多文件上传脚本:
<script type="text/javascript">
var totalsizeOfUploadFiles = 0;
function getFileSizeandName(input)
{
var select = $('#uploadTable');
for(var i =0; i<input.files.length; i++)
{
var filesizeInBytes = input.files[i].size;
var filesizeInMB = (filesizeInBytes / (1024*1024)).toFixed(2);
var filename = input.files[i].name;
//alert("File name is : "+filename+" || size : "+filesizeInMB+" MB || size : "+filesizeInBytes+" Bytes");
if(i<=4)
{
$('#filetd'+i+'').text(filename);
$('#filesizetd'+i+'').text(filesizeInMB);
}
else if(i>4)
select.append($('<tr id=tr'+i+'><td id=filetd'+i+'>'+filename+'</td><td id=filesizetd'+i+'>'+filesizeInMB+'</td></tr>'));
totalsizeOfUploadFiles += parseFloat(filesizeInMB);
$('#totalsize').text(totalsizeOfUploadFiles.toFixed(2)+" MB");
if(i==0)
$('#filecount').text("1file");
else
{
var no = parseInt(i) + 1;
$('#filecount').text(no+"files");
}
}
}
function CloseAndRefresh()
{
opener.location.reload(true);
self.close();
}
</script>
html表单设计:
<body>
<form method="post" id="uploadForm" action="upload" enctype="multipart/form-data">
<table class="span10">
<tr>
<td colspan="3">
<legend>Simple Upload</legend>
</td>
</tr>
<tr>
<td>
<input type="file" name="files[]" multiple="multiple" onchange="getFileSizeandName(this);"/>
</td>
</tr>
<tr>
<td colspan="3">
<div id="uploaddiv">
<table id="uploadTable" class="table table-striped table-bordered">
<tr>
<th>Title</th>
<th>Size</th>
</tr>
<tbody id="tbodyid">
<tr id="tr0">
<td id="filetd0" height="10px" width="50px"></td>
<td id="filesizetd0" height="10px" width="5px"></td>
</tr>
<tr id="tr1">
<td id="filetd1"></td>
<td id="filesizetd1"></td>
</tr>
<tr id="tr2">
<td id="filetd2"></td>
<td id="filesizetd2"></td>
</tr>
<tr id="tr3">
<td id="filetd3"></td>
<td id="filesizetd3"></td>
</tr>
<tr id="tr4">
<td id="filetd4"></td>
<td id="filesizetd4"></td>
</tr>
</tbody>
<tfoot>
<tr>
<td id="filecount"></td><td id="totalsize"></td>
</tr>
</tfoot>
</table>
</div>
</td>
</tr>
<tr>
<td colspan="3">
<button class="btn btn-primary" type="submit" id="startButton" onClick="CloseAndRefresh();">Start</button>
<button class="btn" id="cancelButton">Cancel</button>
</td>
</tr>
</table>
</form>
UploadController.java代码:
@RequestMapping(value = "/upload", method = RequestMethod.POST)
public void UploadReceipts(@RequestParam("files[]") List<MultipartFile> file) throws Exception {
logger.info(" Inside the upload receipts method "+file.size());
for(int i=0; i< file.size(); i++)
{
if(!file.get(i).isEmpty())
{
CommonsMultipartFile cm = (CommonsMultipartFile) file.get(i);
logger.info(" Inside the file upload method "+cm.getOriginalFilename());
simpleUploadService.uploadFileandSaveReceipt(cm);
}
}
}
小智 5
如果在表单提交时使用多个文件上传
<input type="file" name="file[]" multiple>
它创建一个文件数组，并且可以轻松地从该数组中获取文件名。
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