"Thread.currentThread().getName"和"this.getName"之间有什么区别？

Question

这是代码:

import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
import java.util.concurrent.ThreadFactory;


class UnCatchExceptionThread extends Thread{
    public UnCatchExceptionThread(String name){
        this.setName(name);
    }
    @Override
    public void run() {
        System.out.println("Thread name is: " + this.getName());
        throw new RuntimeException();
    }
}

class UnCatchExceptionHandler implements Thread.UncaughtExceptionHandler{
    @Override
    public void uncaughtException(Thread t, Throwable e) {
        System.out.println("catch "  + e + " from " + t.getName());
    }
}

class HandlerFactory implements ThreadFactory{

    @Override
    public Thread newThread(Runnable r) {
        Thread t = new Thread(r);
        t.setUncaughtExceptionHandler(new UnCatchExceptionHandler());
        return t;
    }

}
public class CaptureException {

    public int i;
    /**
     * @param args
     */
    public static void main(String[] args) {
        ExecutorService exec = Executors.newCachedThreadPool(new HandlerFactory());
        exec.execute(new UnCatchExceptionThread("Gemoji"));
    }

}

输出是:

线程名称是:Gemoji
从Thread-1捕获java.lang.RuntimeException

如果我改变了代码

System.out.println("Thread name is: " + this.getName());  

至

System.out.println("Thread name is: " + Thread.currentThread().getName()); 

输出将更改为

线程名称是:Thread-1
从Thread-1捕获java.lang.RuntimeException

为什么？

Answer 1

我假设在某一时刻,UnCatchExceptionThread被传递给您的HandlerFactory.newThread()方法,并执行此方法返回的线程.如果是这样,则创建一个没有名称的新线程,该线程执行作为参数传递的runnable.runnable是UnCatchExceptionThread实例,但正在执行的线程是new Thread(r).

因此,在Runnable run方法中,this是UnCatchExceptionThread的实例,并且具有您给他的名称.但是当前的线程是new Thread(r),它有一个默认名称.