Http获取使用Android HttpURLConnection

use*_*112 59 java android-emulator android-internet

我是Java和Android开发的新手,并尝试创建一个简单的应用程序,它应该联系Web服务器并使用http get将一些数据添加到数据库.

当我使用计算机中的Web浏览器进行呼叫时,它可以正常工作.但是,当我在Android模拟器中执行运行应用程序的调用时,不会添加任何数据.

我已将Internet权限添加到应用程序的清单中.Logcat不会报告任何问题.

任何人都可以帮我弄清楚什么是错的?

这是源代码:

package com.example.httptest;

import java.io.IOException;
import java.net.HttpURLConnection;
import java.net.MalformedURLException;
import java.net.URL;
import android.app.Activity;
import android.os.Bundle;
import android.util.Log;
import android.widget.TextView;

public class HttpTestActivity extends Activity {
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);

        TextView tv = new TextView(this);
        setContentView(tv);

        try {
            URL url = new URL("http://www.mysite.se/index.asp?data=99");
            HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();
            urlConnection.disconnect();
            tv.setText("Hello!");
        }
        catch (MalformedURLException ex) {
            Log.e("httptest",Log.getStackTraceString(ex)); 
        }
        catch (IOException ex) {
            Log.e("httptest",Log.getStackTraceString(ex));
        }   
    }        
}
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Dav*_*555 68

尝试从中获取输入流,然后您可以获取文本数据: -

    URL url;
    HttpURLConnection urlConnection = null;
    try {
        url = new URL("http://www.mysite.se/index.asp?data=99");

        urlConnection = (HttpURLConnection) url
                .openConnection();

        InputStream in = urlConnection.getInputStream();

        InputStreamReader isw = new InputStreamReader(in);

        int data = isw.read();
        while (data != -1) {
            char current = (char) data;
            data = isw.read();
            System.out.print(current);
        }
    } catch (Exception e) {
        e.printStackTrace();
    } finally {
        if (urlConnection != null) {
            urlConnection.disconnect();
        }    
    }
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您也可以使用其他输入流读取器,如缓冲读取器.

问题是当你打开连接时 - 它不会"拉"任何数据.

  • 您应该在finally块中关闭连接 (9认同)

Bha*_*nki 38

这是一个完整的AsyncTask课程

public class GetMethodDemo extends AsyncTask<String , Void ,String> {
    String server_response;

    @Override
    protected String doInBackground(String... strings) {

        URL url;
        HttpURLConnection urlConnection = null;

        try {
            url = new URL(strings[0]);
            urlConnection = (HttpURLConnection) url.openConnection();

            int responseCode = urlConnection.getResponseCode();

            if(responseCode == HttpURLConnection.HTTP_OK){
                server_response = readStream(urlConnection.getInputStream());
                Log.v("CatalogClient", server_response);
            }

        } catch (MalformedURLException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }

        return null;
    }

    @Override
    protected void onPostExecute(String s) {
        super.onPostExecute(s);

        Log.e("Response", "" + server_response);


    }
}

// Converting InputStream to String

private String readStream(InputStream in) {
        BufferedReader reader = null;
        StringBuffer response = new StringBuffer();
        try {
            reader = new BufferedReader(new InputStreamReader(in));
            String line = "";
            while ((line = reader.readLine()) != null) {
                response.append(line);
            }
        } catch (IOException e) {
            e.printStackTrace();
        } finally {
            if (reader != null) {
                try {
                    reader.close();
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
        }
        return response.toString();
    }
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打电话给这个AsyncTask

new GetMethodDemo().execute("your web-service url");
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Xar*_*mer 15

我用callBack(委托)创建了对Activity类的响应.

public class WebService extends AsyncTask<String, Void, String> {

    private Context mContext;
    private OnTaskDoneListener onTaskDoneListener;
    private String urlStr = "";

    public WebService(Context context, String url, OnTaskDoneListener onTaskDoneListener) {
        this.mContext = context;
        this.urlStr = url;
        this.onTaskDoneListener = onTaskDoneListener;
    }

    @Override
    protected String doInBackground(String... params) {
        try {

            URL mUrl = new URL(urlStr);
            HttpURLConnection httpConnection = (HttpURLConnection) mUrl.openConnection();
            httpConnection.setRequestMethod("GET");
            httpConnection.setRequestProperty("Content-length", "0");
            httpConnection.setUseCaches(false);
            httpConnection.setAllowUserInteraction(false);
            httpConnection.setConnectTimeout(100000);
            httpConnection.setReadTimeout(100000);

            httpConnection.connect();

            int responseCode = httpConnection.getResponseCode();

            if (responseCode == HttpURLConnection.HTTP_OK) {
                BufferedReader br = new BufferedReader(new InputStreamReader(httpConnection.getInputStream()));
                StringBuilder sb = new StringBuilder();
                String line;
                while ((line = br.readLine()) != null) {
                    sb.append(line + "\n");
                }
                br.close();
                return sb.toString();
            }
        } catch (IOException e) {
            e.printStackTrace();
        } catch (Exception ex) {
            ex.printStackTrace();
        }
        return null;
    }

    @Override
    protected void onPostExecute(String s) {
        super.onPostExecute(s);

        if (onTaskDoneListener != null && s != null) {
            onTaskDoneListener.onTaskDone(s);
        } else
            onTaskDoneListener.onError();
    }
}
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哪里

public interface OnTaskDoneListener {
    void onTaskDone(String responseData);

    void onError();
}
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您可以根据自己的需要进行修改.这是为了得到