ram*_*esh 24 php google-maps-api-3
在我的一个php应用程序中,我必须从地址中找出该地点的纬度和经度.
我试过这段代码:
$json = file_get_contents("http://maps.google.com/maps/api/geocode/json?address=$address&sensor=false®ion=$region");
$json = json_decode($json);
$lat = $json->{'results'}[0]->{'geometry'}->{'location'}->{'lat'};
$long = $json->{'results'}[0]->{'geometry'}->{'location'}->{'lng'};
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但它显示以下错误:
警告:file_get_contents(http://maps.google.com/maps/api/geocode/json?address=technopark,Trivandrun,kerala,India&sensor = false®ion = IND)[function.file-get-contents]:无法打开流:HTTP请求失败!第4行的D:\ Projects\lon.php中的HTTP/1.0 400错误请求
请帮我解决这个问题.
小智 40
使用curl而不是file_get_contents:
$address = "India+Panchkula";
$url = "http://maps.google.com/maps/api/geocode/json?address=$address&sensor=false®ion=India";
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_PROXYPORT, 3128);
curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0);
$response = curl_exec($ch);
curl_close($ch);
$response_a = json_decode($response);
echo $lat = $response_a->results[0]->geometry->location->lat;
echo "<br />";
echo $long = $response_a->results[0]->geometry->location->lng;
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Cod*_*ver 37
$address = str_replace(" ", "+", $address);
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在file_get_content之前使用上面的代码.意思是,使用以下代码
$address = str_replace(" ", "+", $address);
$json = file_get_contents("http://maps.google.com/maps/api/geocode/json?address=$address&sensor=false®ion=$region");
$json = json_decode($json);
$lat = $json->{'results'}[0]->{'geometry'}->{'location'}->{'lat'};
$long = $json->{'results'}[0]->{'geometry'}->{'location'}->{'lng'};
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它肯定会奏效.由于地址不支持空格,因此它仅支持+符号代替空格.
//add urlencode to your address
$address = urlencode("technopark, Trivandrun, kerala,India");
$region = "IND";
$json = file_get_contents("http://maps.google.com/maps/api/geocode/json?address=$address&sensor=false®ion=$region");
echo $json;
$decoded = json_decode($json);
print_r($decoded);
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