这段代码是python上的一本书中的示例代码.这是一个输入整数并显示整数的总和,总数和平均值的简单程序.但是,当我尝试运行代码时,我在第18行(冒号)收到语法错误.这段代码对我来说非常好.有任何想法吗?
print("type integers, each followed by Enter; or just Enter to finish")
total = 0
count = 0
while True:
line = input("integer: "
if line:
try:
number = int(line)
except ValueError as err:
print(err)
continue
total += number
count += 1
else:
break
if count:
print("count=", count, "total =", total, "mean =", total / count)
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当我尝试运行它时,我收到一个错误:
File "./intproj.py", line 18
else:
^
SyntaxError: invalid syntax
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我在Ubuntu 11.10上使用IDLE作为IDE和python 3.2.2
更新的代码:
print("type integers, each followed by Enter; or just Enter to finish")
total = 0
count = 0
while True:
line = input("integer: ")
if line:
try:
number = int(line)
except ValueError as err:
print(err)
continue
total += number
count += 1
else:
break
if count:
print("count=", count, "total =", total, "mean =", total / count)
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现在得到错误:
File "./intproj.py", line 18
else:
^
SyntaxError: invalid syntax
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固定代码:
print("type integers, each followed by Enter; or just Enter to finish")
total = 0
count = 0
while True:
line = input("integer: ")
if line:
try:
number = int(line)
except ValueError as err:
print(err)
continue
total += number
count += 1
else:
break
if count:
print("count=", count, "total =", total, "mean =", total / count)
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谢谢!
第9行似乎错过了一个 )
更改:
line = input("integer: "
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成
line = input("integer: ")
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该except
行需要缩进以匹配try
和行:
total += number
count += 1
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需要缩进以及否则,if
和else
语句不排队.即代码应该是这样的:
print("type integers, each followed by Enter; or just Enter to finish")
total = 0
count = 0
while True:
line = input("integer: ")
if line:
try:
number = int(line)
except ValueError as err:
print(err)
continue
total += number
count += 1
else:
break
if count:
print("count=", count, "total =", total, "mean =", total / count)
Run Code Online (Sandbox Code Playgroud)
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