使用Python 3解码URL

Question

有没有办法在Python 3中对字符串进行URL解码

采取这样的事情

id%253D184ff84d27c3613d%26quality%3Dmedium

并解码它两次得到

id=184ff84d27c3613d&quality=medium

Answer 1

只需使用urllib.parse.unquote():

>>> import urllib.parse
>>> urllib.parse.unquote('id%253D184ff84d27c3613d%26quality%3Dmedium')
'id%3D184ff84d27c3613d&quality=medium'
>>> urllib.parse.unquote('id%3D184ff84d27c3613d&quality=medium')
id=184ff84d27c3613d&quality=medium

Answer 2

试试这个:

from urllib.parse import unquote
s = 'id%253D184ff84d27c3613d%26quality%3Dmedium'
unquote(unquote(s))

它将返回:

> 'id=184ff84d27c3613d&quality=medium'