将值分配给数组时出现意外结果在c

Question

我正在阅读C编程语言第二版.我参加了这个练习[第1.6节,第 1节,第 13 页.24第2版 ].

编写一个程序来打印输入中单词长度的直方图.可以很容易地绘制水平条形图的直方图; 垂直方向更具挑战性.

我认为一切都很好用,除非我试图确定最后一个字数(VARIABLE tmp)是<= 10还是> 10然后将其分配给count [tmp-1]或count [11]中的相应索引(如果是比...更棒.我甚至不关心打印一个实际的直方图,我现在想拥有一个有效的数组表示.下面是程序运行时的输出.

asdasd 
_________________________________
 1  2  3  4  5  6  7  8  9 10 11 
   (x-axis) Length of words 
---------------------------------
[0 SPACE] [0 NEWLINE] [0 TAB] 
[1 WORD] [0.000 KILOBYTE] [6 CHAR]



6---


ARRAy= 1  1  1  1  1  2  0  0  0  0 

这是我的代码

#include <stdio.h>
#define MAX 10


int main (void) {
    //
    int nc,nw,nt,ns,nl;  //nc = bytes, nw = words, nt = tabs, ns = spaces, nl = newlines
    nc = nw = nt = ns = nl = 0;
    //
    int c;                     //getchar()
    int done = 0;             //don't even know I'm a noob just ignore...
    int tmp = 0;              //last word count (this works well)
    int array[MAX + 1];      //For outputting screen formatters like ---
    int count[11];           //THIS is whats broken random values
    int state = 0;
    int waslast = 0;
    float kbcount = 0;
    for (c = 0; c <= MAX; c++)
    count[c] = 0;

    while (done == 0) {
        c = getchar();
        ++nc;

        if (c == ' ' || c == '\n' || c == '\t') {
            waslast = 1;



            if (c == '\t') {
                ++nt;
                state = tmp;
                tmp = 0;
            }
            else if (c == '\n') {
                ++nl;
                state = tmp;
                tmp = 0;
            }
            else if (c == ' ') {
                ++ns;
                state = tmp;
                tmp = 0;
            }
        }

        if (c == EOF) {
            done = 1;
        }
        else if (c != ' ' && c != '\n' && c != '\t') {
            tmp++;
            state = tmp;
            if (waslast == 1) {
                nw++;
                waslast=0;
            }
            if (nc == 1)
                nw++;
        }

        if (tmp <= 10)
            count[tmp-1]++;       //Completely random assignments
        else
            count[11]++;          //This is broken
    }



    // END WHILE
    //
    //



    printf("\n");
    for (c = 1; c <= MAX + 1; c++) {
        printf("___");

    }

    printf("\n");

    for (c = 1; c <= MAX + 1; c++) {
        array[c] = c;
        printf("%2d ", array[c]);
    }

    printf("\n   (x-axis) Length of words \n");

    for (c = 1; c <= MAX + 1; c++){
        printf("---");
    }

    kbcount = (nc-1)/1024;

    printf("\n[%d SPACE] [%d NEWLINE] [%d TAB] \n[%d WORD] [%.3f KILOBYTE] [%d CHAR]\n\n\n\n%d---\n\n\n",
           ns,nl,nt,nw,kbcount,(nc -(nl+nt+ns))-1,state);

    printf("ARRAy=");
    for (c = 0; c<MAX ;++c)
        printf(" %d ",count[c]);
    return 0;


}

~~

Answer 1

从0开始索引的c数组count[11]++;超出了数组的范围.

11元素数组的有效索引是索引0到10(包括0和10).数组中的第11个元素count是count[10].