将长列表格式化为80列

Question

  try:
    for key in copy['KnownNetworks'].keys():
      if copy['KnownNetworks'][key]['SSID_STR'] == networkDict['name']:
        networkDict['uuid'] = copy['KnownNetworks'][key]['Unique Password ID']
        print 'Found existing reference to wireless password uuid: %s' % networkDict['uuid']
        found = True
  except:
    print 'Key KnownNetworks not found'
  # Clean up top level key

  keychain = '/Library/Keychains/System.keychain'
  arguments = [security,"add-generic-password",'-a',networkDict['name'],'-l',networkDict['name'],'-D','Airport network password','-s',networkDict['uuid'],'-w',networkDict['pass'],'-T','group://Aiport','-T','/System/Library/CoreServices/SystemUIServer.app','-T','/Applications/System Preferences.app','-T','/usr/libexec/airportd',keychain]
  addKeychainPassword(arguments)
  users = '/var/db/dslocal/nodes/Default/users'
  listing = os.listdir(users)
  for plist in listing:

我有一个格式化问题,就是上面的例子,是否有更好的方法来格式化参数列表声明？它是一个子进程调用,所以我需要它作为一个列表,但我想我可以将它转换为字典然后返回列表.我的主要目标是,我希望它适合大多数unix脚本的80 col标准.您想要在清洁代码方面分享哪些技术？

Answer 1

对于超过80列的行,您可以将它们分成多行.这里很容易,因为你有一个清单.

arguments = [security,
             'add-generic-password',
             '-a', networkDict['name'],
             '-l', networkDict['name'],
             '-D', 'Airport network password',
             '-s', networkDict['uuid'],
             '-w', networkDict['pass'],
             '-T', 'group://Aiport',
             '-T', '/System/Library/CoreServices/SystemUIServer.app',
             '-T', '/Applications/System Preferences.app',
             '-T', '/usr/libexec/airportd',
             keychain]

在这里你不仅获得与Python的风格指南遵守的满意温暖的光芒,但它的很多,看的时候代码格式化这种方式传递的参数更容易.

Python布局的官方指南是PEP-8.它有其他分裂长线的例子.