我需要一个RegEx表示一个数值,最多两个小数位大于零,并且在一列中可能有也可能没有零.我还应该补充....整数都很好.请参阅下面的内容,但可能有前导或尾随空格
Good values:
.1
0.1
1.12
123.12
92
092
092.13
Error values:
0
0.0
0.00
00
1.234
-1
-1.2
Anything less than zero
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Tim*_*ker 54
这个怎么样:
^\s*(?=.*[1-9])\d*(?:\.\d{1,2})?\s*$
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说明:
^ # Start of string
\s* # Optional whitespace
(?=.*[1-9]) # Assert that at least one digit > 0 is present in the string
\d* # integer part (optional)
(?: # decimal part:
\. # dot
\d{1,2} # plus one or two decimal digits
)? # (optional)
\s* # Optional whitespace
$ # End of string
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用Python测试:
>>> import re
>>> test = [".1", "0.1", "1.12", "123.12", "92", "092", "092.13", "0", "0.0", "0.00", "00", "1.234", "-1", "-1.2"]
>>> r = re.compile(r"^\s*(?=.*[1-9])\d*(?:\.\d{1,2})?\s*$")
>>> for item in test:
... print(item, "matches" if r.match(item) else "doesn't match")
...
.1 matches
0.1 matches
1.12 matches
123.12 matches
92 matches
092 matches
092.13 matches
0 doesn't match
0.0 doesn't match
0.00 doesn't match
00 doesn't match
1.234 doesn't match
-1 doesn't match
-1.2 doesn't match
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