如何在没有find的情况下在linux shell脚本中根据日期查找和删除文件?

cod*_*boy 6 linux bash shell

请注意,我不能在目标环境中使用"找到"

我需要在linux shell脚本中删除超过7天的所有文件.就像是:

FILES=./path/to/dir
for f in $FILES
do
  echo "Processing $f file..."
  # take action on each file. $f store current file name
  # perhaps stat each file to get the last modified date and then delete files with date older than today -7 days.

done
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我可以用'stat'来做这件事吗?我试图用

find *.gz -mtime +7 -delete
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但发现我不能在目标系统上使用find(没有cron用户的权限,这不能更改).目标系统是Redhat Enterprise.

文件名的格式如下:

gzip>/mnt/target03/rest-of-path/web/backups/DATABASENAME_ date "+%Y-%m-%d".gz

pgl*_*pgl 8

这应该工作:

#!/bin/sh

DIR="/path/to/your/files"
now=$(date +%s)
DAYS=30

for file in "$DIR/"*
do
    if [ $(((`stat $file -c '%Y'`) + (86400 * $DAYS))) -lt $now ]
    then
    # process / rm / whatever the file...
    fi
done
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一点解释:stat <file> -c '%Z'给出文件的修改时间,自文件的UNIX纪元以来为秒,并$(date +%s)给出当前的UNIX时间戳.然后只需要一个简单的检查,看看文件的时间戳加上七天的秒数是否大于当前的时间戳.


Cjo*_*lly 3

既然你在文件名中有时间,那么就用它来计算删除的时间,这里有一些代码可以做到这一点:

该脚本获取自纪元以来的当前时间(以秒为单位),然后计算 7 天前的时间戳。然后,对于每个文件,解析文件名并将每个文件名中嵌入的日期转换为时间戳,然后比较时间戳以确定要删除的文件。使用时间戳可以消除直接处理日期的所有麻烦(闰年、月份中的不同日期等)

实际删除已被注释掉,以便您可以测试代码。

#funciton to get timestamp X days prior to input timestamp
# arg1 = number of days past input timestamp
# arg2 = timestamp ( e.g. 1324505111 ) seconds past epoch
getTimestampDaysInPast () {
    daysinpast=$1
    seconds=$2
    while [ $daysinpast -gt 0 ] ; do
    daysinpast=`expr $daysinpast - 1`
    seconds=`expr $seconds - 86400`
    done
# make midnight
    mod=`expr $seconds % 86400`
    seconds=`expr $seconds - $mod`
    echo $seconds
} 
# get current time in seconds since epoch
getCurrentTime() {
    echo `date +"%s"`
}

# parse format and convert time to timestamp
# e.g. 2011-12-23 -> 1324505111
# arg1 = filename with date string in format %Y-%m-%d
getFileTimestamp () {
    filename=$1
    date=`echo $filename |  sed "s/[^0-9\-]*\([0-9\-]*\).*/\1/g"`
    ts=`date -d $date | date +"%s"`
    echo $ts
}

########################### MAIN ############################
# Expect directory where files are to be deleted to be first 
# arg on commandline. If not provided then use current working
# directory

FILEDIR=`pwd`
if [ $# -gt 0 ] ; then 
    FILEDIR=$1
fi
cd $FILEDIR

now=`getCurrentTime`
mustBeBefore=`getTimestampDaysInPast 7 $now`
SAVEIFS=$IFS
# need this to loop around spaces with filenames
IFS=$(echo -en "\n\b")
# for safety change this glob to something more restrictive
for f in * ; do 
    filetime=`getFileTimestamp $f`
    echo "$filetime lt $mustBeBefore"
    if [ $filetime -lt $mustBeBefore ] ; then
    # uncomment this when you have tested this on your system
    echo "rm -f $f"
    fi
done
# only need this if you are going to be doing something else
IFS=$SAVEIFS
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